Consider the graph of the linear function h(x) = –x + 5. Which could you change to move the graph down 3 units?

Mathematics

2 answers:

UkoKoshka [18]3 years ago

9 0

We are given linear function h(x) = –x + 5.

On comparing with slope-intercept form y = mx+b, we get b=5.

Therefore, y-intercept is at 5.

We need to change to move the graph down 3 units.

<em>According to rules of transformation f(x)+c shift c units up and f(x)-c shift c units down.</em>

Therefore, in order to move the graph down 3 units, we need to subtract given function by 3, we get

y = -x+5 -3

y = -x +2.

Here y-intercept is 2.

<h3>Therefore, correct option is 3rd option: the value of b to 2.</h3>

Yakvenalex [24]3 years ago

6 0

I don't see a b or an m in this function, but generally, a linear function is of the form ax+b. The b in this equation (not sure if it is the same as your b), controls the shift of the function. Lower b by 3, the graph shifts down by 3.

So unless there is a minus sign before b, it has to be lowered by 3. (If there is a minus sign, it has to be increased by 3).

You might be interested in

it takes 52 minutes for 5 people to paint 4 walls. how many minutes does it take 20 people to paint 20 walls

Daniel [21]

34 mins until the paint dries

4 0

3 years ago

A department store sells a pair of shoes with an 87% markup. If the store bought the pair of shoes for $55.25, what is the selli

kolbaska11 [484]

Markup means they sell it for that percentage more than they bought it for. First let's calculate how much they will mark it up for:

$\sf 55.25\cdot 87\%$

Convert 87% into a decimal(87/100):

$\sf 55.25\cdot 0.87$

Multiply:

$\sf\approx 48$

This is how much they'll mark it up, now let's add it to how much they bought it for to find out the selling price:

$\sf 48+55.25\approx\boxed{\sf \$ 103}$