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3 years ago

Consider the graph of the linear function h(x) = –x + 5. Which could you change to move the graph down 3 units?

Mathematics

2 answers:

UkoKoshka [18]3 years ago

9 0

We are given linear function h(x) = –x + 5.

On comparing with slope-intercept form y = mx+b, we get b=5.

Therefore, y-intercept is at 5.

We need to change to move the graph down 3 units.

<em>According to rules of transformation f(x)+c shift c units up and f(x)-c shift c units down.</em>

Therefore, in order to move the graph down 3 units, we need to subtract given function by 3, we get

y = -x+5 -3

y = -x +2.

Here y-intercept is 2.

<h3>Therefore, correct option is 3rd option: the value of b to 2.</h3>

Yakvenalex [24]3 years ago

6 0

I don't see a b or an m in this function, but generally, a linear function is of the form ax+b. The b in this equation (not sure if it is the same as your b), controls the shift of the function. Lower b by 3, the graph shifts down by 3.

So unless there is a minus sign before b, it has to be lowered by 3. (If there is a minus sign, it has to be increased by 3).

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Find the largest and smallest whole number when rounded to the nearest hundred to give 1600.

kifflom [539]

Answer:

Step-by-step explanation:

Smallest and largest whole number which gives 1600 when rounded to the nearest hundred.

The lowest whole number is 1550

The highest while number is 1649

Wheb rounding to the nearest hundred, the tens value which comes after the hundred value is carefully observed, of the tens value is less than 5, then it is rounded down to zero. However, if the tens value is greater than or equal to 5, it is rounded to 1 and added to the hundred value.

Numbers below 1550 will not round to 1600 (nearest 100) also numbers greater than 1649will not round to 1600(nearest 100).butvall numbers in between them will round to 1600 (nearest hundred)

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3 years ago

What is the correct definition for cot theta?

NemiM [27]

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4 years ago

Read 2 more answers

Help ASAP

horrorfan [7]

Answer:

p= $\frac{181}{301}$

Step-by-step explanation:

30100 have dogs, 18100 have cats.

The question simply asks for a union scenario thus the law of AND & OR is applicable.

Therefore:-Those who have both cats and dogs partially have cats.

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3 years ago

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kotykmax [81]

Answer:

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Step-by-step explanation:

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3 years ago

There are 20 machines in a factory. 7 of the machines are defective.

adelina 88 [10]

Answer:

0.1225

Step-by-step explanation:

Given

Number of Machines = 20

Defective Machines = 7

Required

Probability that two selected (with replacement) are defective.

The first step is to define an event that a machine will be defective.

Let M represent the selected machine sis defective.

P(M) = 7/20

Provided that the two selected machines are replaced;

The probability is calculated as thus

P(Both) = P(First Defect) * P(Second Defect)

From tge question, we understand that each selection is replaced before another selection is made.

This means that the probability of first selection and the probability of second selection are independent.

And as such;

P(First Defect) = P (Second Defect) = P(M) = 7/20

So;

P(Both) = P(First Defect) * P(Second Defect)

PBoth) = 7/20 * 7/20

P(Both) = 49/400

P(Both) = 0.1225

Hence, the probability that both choices will be defective machines is 0.1225

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3 years ago