With digits 8, 5, and 6, an odd number must end in 5.
So far, we have _ _ 5.
The 8 is in the hundreds place.
Now we have 8_5.
The only place left for the 6 is the tens place.
The number is 865.
Answer:
x < -5
Step-by-step explanation:
Distribute 4 to x and 10: 4x + 40 < 20
Subtract 40 from both sides: 4x < -20
Divide by 4: x < -5
Answer:
5
Step-by-step explanation:
<em>- What two consecutive odd integers have a sum of 48</em>?
23 + 25 = 48
- <em>Two negative consecutive integers have a sum of -45. What are the integers?
</em>
<em />-22 + -23
- <em>The sum of two consecutive integers 75. What are the two integers?</em>
37 + 38 = 75
- <em>What <u>three</u> consecutive odd integers have a sum of 81?
</em>
<em />25 + 27 + 29 = 81
Hope I could help! Have a good one. I believe that is all of the unanswered questions. If I missed one, let me know!<em />
