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liq [111]
3 years ago
10

How to factor a quadratic equation and find the vertex?

Mathematics
1 answer:
Jet001 [13]3 years ago
6 0
To convert a quadratic<span> from y = ax</span>2<span> + bx + c form to </span>vertex<span> form, y = a(x - h)</span>2+ k, you use the process of completing the square. Let's see an example. Convert y = 2x2<span>- 4x + 5 into </span>vertex<span> form, and state the </span>vertex<span>.</span>
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yuradex [85]

Answer:

x = 12

Step-by-step explanation:

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3 years ago
Find the equation, (f(x) = a(x - h)2 + k), for a parabola containing point (2, -1) and having (4, -3) as a vertex. What is the s
Nataliya [291]

Answer:

f(x)=\frac{1}{2}x^2-4x+5

Step-by-step explanation:

A parabola is written in the form

f(x)=a((x-h)^2+k) (1)

where:

h is the x-coordinate of the vertex of the parabola

ak is the y-coordinate of the vertex of the parabola

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For the parabola in the problem, we know that the vertex has  coordinates (4,-3), so we have:

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From this last equation, we get that a=\frac{-3}{k} (3)

Substituting (2) and (3) into (1) we get the new expression:

f(x)=-\frac{3}{k}((x-4)^2+k) = -\frac{3}{k}(x-4)^2 -3 (4)

We also know that the parabola  contains the point (2,-1), so we can substitute

x = 2

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Into eq.(4) and find the value of k:

-1=-\frac{3}{k}(2-4)^2-3\\-1=-\frac{3}{k}\cdot 4 -3\\2=-\frac{12}{k}\\k=-\frac{12}{2}=-6

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f(x)=\frac{1}{2}((x^2-8x+16)-6)=\frac{1}{2}(x^2-8x+10)=\frac{1}{2}x^2-4x+5

6 0
3 years ago
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AE = EC

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collect like terms:

3x - x = 12 + 4

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divide both sides by 2:

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