Question

A male student of the author has a measured pulse rate of 52 beats per

Answer 1

Answer:

$z=-1.49$

Step-by-step explanation:

$\text{Standard Score, z} =\dfrac{X-\mu}{\sigma} where:\\\\Mean Pulse rate, \mu =67.3 beats per minute\\Standard Deviation, \sigma = 10.3 beats per minute.$

For a male student who has a measured pulse rate of 52 beats per  minute.

Raw Score, X =52 beats per  minute.

Therefore:

$\text{Standard Score, z} =\dfrac{52-67.3}{10.3}\\z=-1.49$

Since the usual pulse rates are within 2 standard deviations of the mean, a z-score of -1.49 tells us that the selected student's pulse rate is within the usual pulse rates.