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goldenfox [79]
3 years ago
9

Find the value of z when x=10.5, a=0.357 and b=0.226.

Mathematics
1 answer:
boyakko [2]3 years ago
6 0

Where's the equation that contains "z"?

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Consider two circular swimming pools. Pool A has a radius of 48 feet, and Pool B has a diameter of 29.46 meters. Complete the de
Ber [7]

Answer: pool B has a greater circumference.

Step-by-step explanation:

The formula for determining the circumference if a circle is expressed as

Circumference = 2πr

Where

r represents the radius of the circle.

π is a constant whose value is 3.14

Pool A has a radius of 48 feet.

1 foot ≈ 0.305 meters

48 feet = 48 × 0.305 = 14.64 meters

The circumference of pool A is

2 × 3.14 × 14.64 = 91.94 meters

Pool B has a diameter of 29.46 meters. Radius = diameter/2

Radius of pool B = 29.46/2 = 14.73 meters

The circumference of pool B is

2 × 3.14 × 14.73 = 92.5 meters

Therefore, pool B has a greater circumference.

7 0
3 years ago
Please answer correctly I will mark you Brainliest!
BartSMP [9]

Answer:

1047.12in³

Step-by-step explanation:

The volume of the sphere is:

V= 4/3 πr³

Where r is radius

Therefore the volume of each pinata is:

V= 4/3 x π x 5³

V= 523.6in³

The total:

V = 523.6 + 523.6 = 1047.12in³

7 0
3 years ago
The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e
I am Lyosha [343]

Answer:

(a) The proportion of tenth graders reading at or below the eighth grade level is 0.1673.

(b) The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.198, 0.260).

Step-by-step explanation:

Let <em>X</em> = number of students who read above the eighth grade level.

(a)

A sample of <em>n</em> = 269 students are selected. Of these 269 students, <em>X</em> = 224 students who can read above the eighth grade level.

Compute the proportion of students who can read above the eighth grade level as follows:

\hat p=\frac{X}{n}=\frac{224}{269}=0.8327

The proportion of students who can read above the eighth grade level is 0.8327.

Compute the proportion of tenth graders reading at or below the eighth grade level as follows:

1-\hat p=1-0.8327

        =0.1673

Thus, the proportion of tenth graders reading at or below the eighth grade level is 0.1673.

(b)

the information provided is:

<em>n</em> = 709

<em>X</em> = 546

Compute the sample proportion of tenth graders reading at or below the eighth grade level as follows:

\hat q=1-\hat p

  =1-\frac{X}{n}

  =1-\frac{546}{709}

  =0.2299\\\approx 0.229

The critical value of <em>z</em> for 95% confidence interval is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Compute the 95% confidence interval for the population proportion as follows:

CI=\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

     =0.229\pm 1.96\times \sqrt{\frac{0.229(1-0.229)}{709}}\\=0.229\pm 0.03136\\=(0.19764, 0.26036)\\\approx (0.198, 0.260)

Thus, the 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.198, 0.260).

5 0
3 years ago
Distance formula for cars coming from perpendicular roads
Serggg [28]
The answer to the question is
6 0
3 years ago
The curved surface area of a cylinder is one third of its total surface area and the height is 5
frosja888 [35]

Answer:

Diameter of cylinder = 12 cm

Step-by-step explanation:

Given:

Height of cylinder = 5 cm

Total surface area of cylinder = 3 x [Curved surface area of a cylinder]

Find:

Diameter of cylinder

Computation:

Total surface area of cylinder = 3 x [Curved surface area of a cylinder]

πr²h = 3[2πrh]

πr²h = 6πrh

Radius of cylinder = 6 cm

Diameter of cylinder = 2 x Radius of cylinder

Diameter of cylinder = 2 x 6

Diameter of cylinder = 12 cm

3 0
3 years ago
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