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Andrews [41]
2 years ago
6

Write an equation for the line perpendicular to the line y= -2/3+7 which passes through the point (-5,6)

Mathematics
1 answer:
zysi [14]2 years ago
8 0
Y = -2/3x + 7.....the slope here is -2/3. A perpendicular line will have a negative reciprocal slope. All tht means is take the original slope, flip it, and change the sign. So we take -2/3....flip it making it -3/2.....change the sign making it 3/2. So ur perpendicular line will have a slope of 3/2.

y = mx + b
slope(m) = 3/2
(-5,6)....x = -5 and y = 6
now sub and find b, the y int
6 = 3/2(-5) + b
6 = -15/2 + b
6 + 15/2 = b
12/2 + 15/2 = b
27/2 = b
so ur perpendicular equation is : y = 3/2x + 27/2 <==
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Answer:

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Step-by-step explanation:

Please remember the concept

If sides are in the ratio of a:b

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It is given sum of their perimeter is 117.

Let the small triangle has perimeter as x.

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-65 and -585 works.

So, we can rewrite it as

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