The liquid disilicon hexachloride reacts with water to form solid silicon dioxide, hydrogen chloride gas and hydrogen gas are
When liquid disilicon hexachloride reacts with water to form solid silicon dioxide , hydrogen chloride gas and hydrogen gas , the following chemical equation is:
now , we have to balance the eqaution,
Reactants product
Si 2 1
Cl 6 1
H 2 3
O 1 2
Multiply 4 with 2 with and 6 with HCL, we get
now ,
Reactant Product
Si 2 2
Cl 6 6
H 8 8
O 4 4
Thus, we get the desire equtions.
The liquid disilicon hexachloride reacts with water to form solid silicon dioxide, hydrogen chloride gas and hydrogen gas are
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Your Answer would be false,
Gasses do expand because they do not have a volume. liquids do not expand to fill their container.
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The molarity of a saline solution that contain 0.900 g NaCl (58.44 g/mol) dissolved in 100.0 ml solution is 0.15 M
<u><em>calculation</em></u>
Molarity = moles /volume in liters
volume in liters = 100.0 ml / 1000 = 0.1 L
moles = mass÷ molar mass
= 0.900 g ÷58.44 g/mol =0.015 moles
molarity is therefore = 0.015 moles / 0.1 L =0.15 M
Answer:
See image attached and explanation
Explanation:
I have attached a detailed mechanism of the reaction to this answer. This reaction occurs by SN1 mechanism. It implies that the transition state involves a carbocation.
However, the initial carbocation formed is a primary carbacation. Remember that the order of stability of carbocations is methyl< primary < secondary< tertiary. This means that tertiary carbocations are the most stable carbocations. Tertiary carbocations are those in which the carbon atom bearing the carbon atom is attached to three other carbon atoms.
In the mechanism below, the substrate converts from a primary to a tertiary cabocation (most stable) by a 1,2-alkyl shift as shown giving the 3-ethoxy-3-methylpentane product.