Answer:
464.1 J absorbed.
Explanation:
Given data:
Specific heat of zinc = 0.39 J/g°C
Mass of zinc = 34 g
Temperature changes = 22°C to 57°C
Energy absorbed or released = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 57°C - 22°C
ΔT = 35°C
Q = m.c. ΔT
Q = 34 g. 0.39 J/g°C. 35°C
Q = 464.1 J
Answer: 10
Explanation:
The detailed solution is contained in the image attached. The molar mass of hydrated and anhydrous salts are obtained and the number of moles of hydrated and hydrated salts are equated. The masses of hydrated and anhydrous salts are gives in the question and are simply substituted accordingly. This can now be used to obtain the number of molecules of water of crystallization as required in the question.
Mechanical energy<span> of </span>an object<span> can be the result of </span>its<span> motion
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Answer:
See the answer below.
Explanation:
Fire has three major components:
- Heat
- Smoke
- Gases ( in form of CO, CO2 etc)
If the victim had died as a result of the fire, he/he would have inhaled smoke and hot gases from the fire. These components would have resulted in traces of burns and soot deposition in the trachea and lungs as well as traces of CO in the blood of the victim.
If the analysis of the victim's corpse does not reflect some of the results above, it can be effectively concluded that the victim has been dead before the fire.
<em>The single most important indicator of death by the fire would be the presence of CO in the blood of the victim's corpse. All others might be to a less significant degrees.</em>
Answer:
426 mg = 4.26 x 10² mg
Explanation:
1 cup = 237.6 mL x 1 L/1000 mL = 0.2376 L
We divide the liters of milk the student drinks into the volume in liters of a cup to calculate the number of cups the student drinks per day:
number of cups per day = 0.318 L/0.2376 L = 1.34 cup
Now, we multiply the number of cups by the amount of calcium that a cup of milk has:
amount of calcium = 1.34 cup x 318 mg = 426 mg = 4.26 x 10² mg
Therefore, the student gets 426 mg (or 4.26 x 10² mg) of calcium in one day.
