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Korolek [52]
3 years ago
10

2x+y=10 Y=5x-11 Solve the system of equations by substitution

Mathematics
2 answers:
antoniya [11.8K]3 years ago
8 0
The answer would be (3,4)
Zina [86]3 years ago
7 0
2x+5x-11=10!
So once you combine like terms - 2x+5x, you end up with 7x-11=10
You then have to add 11 to both sides of the equal sign and you get 7x=21. If you divide both sides by 7, you end up with x=3.
Did you need what Y was, too ? If so, you just go back to the original problem:
2(3)+y=10
2 times 3 = 6+y=10.
Subtract 6 from both sides and you get Y=4!
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Solve this inequality:<br> -12a +7&lt;31
vagabundo [1.1K]

Answer:

a > -2

Step-by-step explanation:

-12a +7<31

Subtract 7 from each side

-12a +7-7<31-7

-12a <24

Divide by -12, remembering to flip the inequality

-12a/-12 >24/-12

a > -2

7 0
3 years ago
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What is 10 times 2 divided by 4 plus 3
PtichkaEL [24]
The answer would be 8!!
4 0
3 years ago
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26=4v+3v+12 can anyone help?
motikmotik

Answer:

Step-by-step explanation:

Combine like terms

3v + 4v

26=7v+12

Subtract    12  from both sides of the equation

26-12

12-12

14=7v

Simplify

so subtract the 12's

Divide both sides of the equation by the same term

14 divided by 7

7 divided by 7

Simplify

do the division and move the term on the other side and it would be

v=2

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v=2

4 0
3 years ago
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the sum of two numbers is 35 think of 2 numbers that make up 35 and then subtract them and see if they make 15 {no the answer is
JulijaS [17]
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8 0
3 years ago
Jasmine purchased 3 bags of hot cheetos and 2 packs of sour patch kids from the vending machine and spent 5.25. Michael also loa
Charra [1.4K]

Answer:

cost of a bag of hot Cheetos = 0.75 and cost of a pack of sour patch kids = 1.5

Step-by-step explanation:

Let the cost of a bag of hot cheetos be c

Let the cost of a pack of sour patch kids be k

Thus, for Jasmine, the equation will be;

3c + 2k = 5.25 - - - - (eq1)

For Michael, the equation will be;

7c + 3k = 9.75 - - - - - (eq2)

We will use method of elimination to solve this.

Multiply (eq 1) by 3 and (eq 2) by 2 to give;

9c + 6k = 15.75 - - (eq4)

14c + 6k = 19.5 - - -(eq5)

Subtract (eq4) from (eq 5) to get;

5c = 19.5 - 15.75

5c = 3.75

c = 3.75/5

c = 0.75

Put 0.75 for c in (eq 4) to get;

9(0.75) + 6k = 15.75

6.75 + 6k = 15.75

6k = 15.75 - 6.75

6k = 9

k = 9/6

k = 1.5

Thus; cost of a bag of hot Cheetos = 0.75 and cost of a pack of sour patch kids = 1.5

7 0
3 years ago
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