c=52, a=2b+8
<span>
Pythagorean Theorem = a^2+b^2=c^2</span>
<span>
(2b+8)^2+b^2=52^2</span>
<span>
<span>
4b^2+32b+64+b^2=2704</span></span>
<span><span>
5b^2+32b-2640=0 </span></span>
<span>
b=20 </span>
a= 2(20)+8 =
48
<span>48+20+52
= 120</span>
<em>The question has missing details. However, general questions that could be asked is as follows:</em>
<em>(1) The number of miles traveled after using (say) 5 gallons</em>
<em>(2) The number of gallons used after traveling for (say) 36 miles</em>
Answer:
See Explanation
Step-by-step explanation:
Given
A linear equation is represented as:
Where
and
c, in this question represents the initial capacity of the tank.
So, the initial capacity is 120 liters
Solving (a): r = 5
<em>60 miles traveled</em>
Solving (b): s = 36
Collect like terms
Solve for r
<em>42 gallons used</em>
Answer:
The ball is in the air for approximately 3.27 seconds ⇒ answer A
Step-by-step explanation:
* Lets explain how to solve the problem
- The height of the ball is modeled by the function
h(t) = -4.9 t² + 16 t
- We need to find the time that the ball is in the air
- The ball is in the air from its initial position and then return to the
same position
- That means h(t) = 0 because h(t) represent the height of the ball
from its initial position
∵ h(t) = -4.9 t² + 16 t
∵ h(t) = 0
∴ 0 = -4.9 t² + 16 t
- Add 4.9 t² to both sides
∴ 4.9 t² = 16 t
- Subtract 16 t from both sides
∴ 4.9 t² - 16 t = 0
- Take t as a common factor
∴ t (4.9 t - 16) = 0
- Equate each factor by 0
∴ t = 0 and 4.9 t - 16 = 0
∵ 4.9 t - 16 = 0 ⇒ add 16 for both sides
∴ 4.9 t = 16
- Divide both sides by 4.9
∴ t = 3.2653
∴ t = 0 ⇒ initial position
∴ t = 3.2653 seconds ⇒ final position
* <em>The ball is in the air for approximately 3.27 seconds</em>
