Question 1
cos(C) = adj/hyp
cos(C) = BC/AC
cos(C) = 15/17
Answer: Choice C) 15/17
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Question 2
sin(E) = opp/hyp
sin(E) = FD/DE
sin(E) = 24/25
So angle E is the answer
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Question 3
AC is the adjacent side to the given angle A = 33 degrees
AB = 14 is the hypotenuse
cos(angle) = adjacent/hypotenuse
cos(33) = x/14
14*cos(33) = x
x = 14*cos(33)
x = 11.741
x = 11.7
Answer: 11.7
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Question 4
x = length of board
cos(angle) = adj/hyp
cos(55) = 6/x
x*cos(55) = 6
x = 6/cos(55)
x = 10.46068
x = 10.5
Answer: 10.5
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Question 5
112 is the adjacent side to the given angle 62 degrees
x = height of building, which is the opposite leg
tan(angle) = opp/adj
tan(62) = x/112
112*tan(62) = x
x = 112*tan(62)
x = 210.641364
x = 210.6
Answer: 210.6
Answer:
Here we will use the relation:
Density = mass/volume.
We know that:
Mass = 1485g
Volume = 750L
Density = 1485g/750L = 1.98 g/L
We do not have the options in order to select the correct one, but knowing this density, we can suppose the possible gases.
Two "common" gases with densities similar to this one are:
Carbon Dioxide, with d = 1.977 g/L
Dinitrogen Monoxide, with d = 1.977 g/L
In both cases, if we round up we will get the same density that we calculated at the beginning, so either of these can be the correct option.
Answer:
208 
Step-by-step explanation:
We can find the area of the net by adding up the area of each of the 6 rectangles that make up the net. Since two of each rectangle are the same, we only have to find the area of the 3 different sized rectangles and multiply each by 2.
Rectangle pairs are:
- Left rectangle and right rectangle
- Top rectangle and the rectangle above the bottom rectangle
- Bottom rectangle and the rectangle surrounded by all for sides
Now, let's solve the question.
Left rectangle:
6 x 4 = 24, rectangle has area of 24 squared cm
Top rectangle:
6 x 8 = 48, rectangle has area of 48 squared cm
Bottom rectangle:
4 x 8 = 32, rectangle has area of 32 squared cm
Add up the areas:
(24 x 2) + (48 x 2) + (32 x 2) = 208
The rectangle has a surface area of 208 squared cm
Answer:
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