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3 years ago

Can someone help me with this

Mathematics

2 answers:

Dmitrij [34]3 years ago

5 0

TanA=(opposite side)/(adjacent side), in this case:

tanA=8/15

Monica [59]3 years ago

5 0

Your answer would be 8/15. You just have to take the opposite number as your dominator. :)

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Given the arithmetic sequence: u(1)= 124, u(2)= 117, u(3)= 110, u(4)=103,...

omeli [17]

We are given

arithmetic sequence: u(1)= 124, u(2)= 117, u(3)= 110, u(4)=103

so, first term is 124

u(1)= 124

now, we can find common difference

$d=u(2)-u(1)$

$d=117-124$

$d=-7$

now, we can find kth term

$u(k)=u(1)+(k-1)d$

now, we can plug values

and we get

$u(k)=124+(k-1)*-7$

$u(k)=124-7k+7$

$u(k)=131-7k$

u(k) must be negative

so,

$u(k)=131-7k$

$131-7k$

now, we can solve for k

$7k>131$

$k>18.714$

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3 years ago

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DochEvi [55]

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Linear function has a form of,

$y=mx+n$

Then calculate the slope m using the coordinates of two points. Let say A(x1, y1) and B(x2, y2),

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From here you solve the equation for n,

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