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AveGali [126]
3 years ago
7

A washer and a dryer cost $900 combined. The washer costs $50 less than the dryer. What is the cost of the dryer?

Mathematics
2 answers:
Mamont248 [21]3 years ago
6 0

the answer is thank you $500


MariettaO [177]3 years ago
4 0
The dyer costs a total of $500
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Jacks average in math for the first nine weeks was an 88 . His second nine weeks average decreased 12.5% what was his average fo
ikadub [295]

10% of 88 = 8.8

2.5% of 88 = 2.2

2.2 + 8.8 = 11

88 - 11 = 77

7 0
3 years ago
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The prism below is made of cubes which measure 1/3 of an inch on one side what is the volume
EastWind [94]

Answer:

Volume of rectangular prism = 10/9 inch³

Step-by-step explanation:

Given:

Size of each cube = 1/3 inch

Find:

Volume of rectangular prism

Computation:

Length of rectangular prism = 2 x [1/3]

Length of rectangular prism = 2/3 inch

Width of rectangular prism = 3 x [1/3]

Width of rectangular prism = 3/3

Width of rectangular prism = 1 inch

Height of rectangular prism = 5 x [1/3]

Height of rectangular prism = 5/3 inch

Volume of rectangular prism = Length x Width X Height

Volume of rectangular prism = [2/3] x [1] x [5/3]

Volume of rectangular prism = 10/9 inch³

7 0
2 years ago
The holding period of property acquired by gift may begin on:
maw [93]

Answer:

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
if something starts up costing 500, and then is marked down by 25% on rack of three separate occasions, what is the final price?
Fed [463]
The final price is $475 
5 0
3 years ago
Suppose that S is the set of successful students in a classroom, and that F stands for the set of freshmen students in that clas
lora16 [44]

Answer:

b) 24

Step-by-step explanation:

We solve building the Venn's diagram of these sets.

We have that n(S) is the number of succesful students in a classroom.

n(F) is the number of freshmen student in that classroom.

We have that:

n(S) = n(s) + n(S \cap F)

In which n(s) are those who are succeful but not freshmen and n(S \cap F) are those who are succesful and freshmen.

By the same logic, we also have that:

n(F) = n(f) + n(S \cap F)

The union is:

n(S \cup F) = n(s) + n(f) + n(S \cap F)

In which

n(S \cup F) = 58

n(s) = n(S) - n(S \cap F) = 54 - n(S \cap F)

n(f) = n(F) - n(S \cap F) = 28 - n(S \cap F)

So

n(S \cup F) = n(s) + n(f) + n(S \cap F)

58 = 54 - n(S \cap F) + 28 - n(S \cap F) + n(S \cap F)

n(S \cap F) = 24

So the correct answer is:

b) 24

3 0
3 years ago
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