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3 years ago

Given the function g(x) = 6(4)x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3.

1 answer:

5 0

g(x) = 6(4)x, Section A is from x = 0 to x = 1. Your "6(4)x" needs to be written as

g(x) = 6(4)^x, where the " ^ " indicates exponentiation.

The average rate of change of g(x) from x= 0 to x=1 is:

6(4)^1 - 6(4)^0 24 - 6
a.r.c. = ----------------------- = ----------- = 18 (answer)
1-0 1

Now do the same thing for x = 1 to x = 2.

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Answer:

Thus, the coffee shop is willing to supply 6 pounds per week at a price of $4 per pound.

Step-by-step explanation:

We are given the following information in the question:

The marginal price per pound (in dollars) is given by:

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$P(x) = \displaystyle\int p'(x)~dx =\displaystyle\int\displaystyle\frac{208}{(x+7)^2}~dx\\\\P(x) = \frac{-208}{(x+7)} + c\\\\\text{where c is the constant of integration.}$

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Thus, we are given that

P(9) = 7

Putting the values, we get,

$P(x) = \displaystyle\frac{-208}{(x+7)} + c\\\\P(9) = 7\\\\\displaystyle\frac{-208}{(9+7)} + c = 7\\\\c = 7 + \frac{208}{16} = 20$

$P(x) = \displaystyle\frac{-208}{(x+7)} + 20$

Now, we have to find how many pounds it would be willing to supply at a price of $4 per pound.

P(x) = 4

$P(x) = \displaystyle\frac{-208}{(x+7)} + 20 = 4\\\\\frac{-208}{x+7} = -16\\\\x + 7 = 13\\x = 6$

Thus, the coffee shop is willing to supply 6 pounds per week at a price of $4 per pound.

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3 years ago

Gina looks at the architectural plan of a four-walled room in which the walls meet each other at right angles. The length of one

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Answer:

For a better understanding of the solution provided here, please find the diagram attached.

In the diagram, ABCD is the room.

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Step-by-step explanation:

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3 years ago

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