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Alecsey [184]
3 years ago
7

The function k(x) = (g · h)(x) is graphed below, where g is an exponential function and h is a linear function.

Mathematics
2 answers:
MaRussiya [10]3 years ago
4 0
D is the correct answer you can also use desmos just search it up!
almond37 [142]3 years ago
3 0

<u>Option D is correct:</u> h(x) = 3x

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Solve: m/9=2/3<br><br> This is for 6th grade math
SSSSS [86.1K]

Answer:

m=6

Step-by-step explanation:

2/3 = 6/9

9 divided by 3 = 3

3 + 3 = 6

therefore your answer is 6

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I need help on this thank you​
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Answer:

B. lines BE and CG have to be parallel.

Step-by-step explanation:

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Given the function f(x)=-8x2+8x+9,state whether the vertex represents a maximum or minimum point for the function.
Lelechka [254]
8x2+8x+9
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aleksley [76]
To divide scientific notation, divide the decimals and subtract the powers of 10 for a result of 8.6/3.2=2.6875 multiplied by ten to the 8-3=5. B is the correct answer.
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3 years ago
The average score of all golfers for a particular course has a mean of 71 and a standard deviation of 3. Suppose 36 golfers play
Zielflug [23.3K]

Answer:

.0228

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 71, \sigma = 3, n = 36, s = \frac{3}{\sqrt{36}} = 0.5

Find the probability that the average score of the 36 golfers exceeded 72.

This is 1 subtracted by the pvalue of Z when X = 72. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{72 - 71}{0.5}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

7 0
3 years ago
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