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monitta
3 years ago
15

Find the discriminant of 3x^2-10x=-2

Mathematics
1 answer:
Oksanka [162]3 years ago
7 0

Answer:

76

Step-by-step explanation:

given a quadratic equation in standard form : ax² + bx + c = 0 : a ≠ 0

then the discriminant is Δ = b² - 4ac

given 3x² - 10x = - 2 ( add 2 to both sides )

3x² - 10x + 2 = 0 ← in standard form

with a = 3, b = - 10 and c = 2

b² - 4ac = (- 10)² - (4 × 3 × 2) = 100 - 24 = 76


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What is a formula for the nth term of the given sequence?<br> 36, 24, 16...
SpyIntel [72]

Answer:

The formula to find the nth term of the given sequence is 54 · \frac{2}{3} ^{n}

Step-by-step explanation:

The formula for nth term of an geometric progression is :

a_{n} = \frac{a_{1}(r^{n})}{r}

In this example, we have a_{1} = 36 (the first term in the sequence) and

r = \frac{2}{3} (the rate in which the sequence is changing).

Knowing what the values for r and a_{1} are, now we can solve.

a_{n} = \frac{a_{1}(r^{n})}{r} = \frac{36 (\frac{2}{3} ^{n}) }{\frac{2}{3} } = 54 · \frac{2}{3} ^{n}

Therefore, the formula to find the nth term of the given sequence is

54 · \frac{2}{3} ^{n}

3 0
3 years ago
It took 5 hours to mow 4 lawns. At that rate, how long would it take to mow 7 lawns?
Elanso [62]
1.25 hours for each lawn. 1.25 x 7 = 8.75.
8 0
3 years ago
PLEASE HELP ME I CANT FAIL
insens350 [35]
The correct answer is C


Explain

The graph is given

F(x) is given -2^x

By putting x= - 3 in the first equation
G(x) = -9

Which is false


by putting x= -3 in the second equation

g(x) is also equal -9

Which is false


Hope this help you :D
5 0
3 years ago
Standard form. (x+8)(x−6)
vovikov84 [41]

Answer:

x² + 2x - 48

Step-by-step explanation:

( x + 8 ) ( x - 6 )

=  x ( x - 6 ) + 8 ( x - 6 )

= x*x - 6*x + 8*x + 8*( - 6 )

= x² - 6x + 8x  - 48

= x² + 2x - 48

4 0
1 year ago
Read 2 more answers
Is the point (1, -3) a solution to the system? Show all work
Studentka2010 [4]

Answer:

The point P(1,-3) is not a solution to the system.

Step-by-step explanation:

Given  \left \{ {{y-x+2}} \right.  

Let a point be P(1,-3)

Here x = 1 ; y = -3

Substituting the values of x,y in the function

\left \{ {{y-x+2}} \right.

For y<x-1

-3 < 1-1

-3<0 (True)

now for,

y>-x+2

-3 > -1 + 2

-3 > 1 (False)

Hence the point is not a solution to the system.

6 0
3 years ago
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