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myrzilka [38]
3 years ago
6

3÷5 long division steps​

Mathematics
1 answer:
ZanzabumX [31]3 years ago
6 0

Answer:

0.6

Step-by-step explanation:

step by step on the photo.

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HELP PLEASE!!!!ASAP Giving out brainliest
QveST [7]
It would be 10 as translating the line doesn't make it bigger or smaller<span />
8 0
3 years ago
Please help w this! Its a calculus question! look at the picture for the problem,
neonofarm [45]

Since you mentioned calculus, perhaps you're supposed to find the area by integration.

The square is circumscribed by a circle of radius 6, so its diagonal (equal to the diameter) has length 12. The lengths of a square's side and its diagonal occur in a ratio of 1 to sqrt(2), so the square has side length 6sqrt(2). This means its sides occur on the lines x=\pm3\sqrt2 and y=\pm3\sqrt2.

Let R be the region bounded by the line x=3\sqrt2 and the circle x^2+y^2=36 (the rightmost blue region). The right side of the circle can be expressed in terms of x as a function of y:

x^2+y^2=36\implies x=\sqrt{36-y^2}

Then the area of this circular segment is

\displaystyle\iint_R\mathrm dA=\int_{-3\sqrt2}^{3\sqrt2}\int_{3\sqrt2}^{\sqrt{36-y^2}}\,\mathrm dx\,\mathrm dy

=\displaystyle\int_{-3\sqrt2}^{3\sqrt2}(\sqrt{36-y^2}-3\sqrt2)\,\mathrm dy

Substitute y=6\sin t, so that \mathrm dy=6\cos t\,\mathrm dt

=\displaystyle\int_{-\pi/4}^{\pi/4}6\cos t(\sqrt{36-(6\sin t)^2}-3\sqrt2)\,\mathrm dt

=\displaystyle\int_{-\pi/4}^{\pi/4}(36\cos^2t-18\sqrt2\cos t)\,\mathrm dt=9\pi-18

Then the area of the entire blue region is 4 times this, a total of \boxed{36\pi-72}.

Alternatively, you can compute the area of R in polar coordinates. The line x=3\sqrt2 becomes r=3\sqrt2\sec\theta, while the circle is given by r=6. The two curves intersect at \theta=\pm\dfrac\pi4, so that

\displaystyle\iint_R\mathrm dA=\int_{-\pi/4}^{\pi/4}\int_{3\sqrt2\sec\theta}^6r\,\mathrm dr\,\mathrm d\theta

=\displaystyle\frac12\int_{-\pi/4}^{\pi/4}(36-18\sec^2\theta)\,\mathrm d\theta=9\pi-18

so again the total area would be 36\pi-72.

Or you can omit using calculus altogether and rely on some basic geometric facts. The region R is a circular segment subtended by a central angle of \dfrac\pi2 radians. Then its area is

\dfrac{6^2\left(\frac\pi2-\sin\frac\pi2\right)}2=9\pi-18

so the total area is, once again, 36\pi-72.

An even simpler way is to subtract the area of the square from the area of the circle.

\pi6^2-(6\sqrt2)^2=36\pi-72

6 0
3 years ago
Jimmy sold a book for $69.95 on Cheggs.com. The state had to added a 8% tax his book. How much was
kari74 [83]

Answer:

$5.60

Step-by-step explanation:

Multiply the price of your book, $69.95 by the tax .08

69.95 x 0.08 = 5.596, rounded up to 5.60

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3 years ago
Can someone please help me with this?? I would love the help!!
iris [78.8K]
Just write I have my own problems to deal with.
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3 years ago
Write an algebraic expression that represents the following statement: “7 less than the quotient of 5 and n" *
IrinaK [193]

\huge\boxed{\boxed{\bold{\frac{5}{n}-7}}}

\hrulefill

We'll start with the expression for the quotient of 5 and n, which means we'll use division:

\frac{5}{n}

Now we find 7 less than that, meaning we'll use subtraction:

\frac{5}{n}\bold{-7}

5 0
3 years ago
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