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marusya05 [52]
3 years ago
10

The sample space, S, for flipping a fair coin three times is shown

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
3 0

Answer: \frac{7}{8}

Step-by-step explanation:

Given

Sample space is ={HHH,THH,HTH,HHT,TTH,THT,HTT,TTT}

There are 8 element in sample space which indicates the outcome of tossing a coin three times

Probability of obtaining at least one head=1-P(\text{0 head})

P(\text{0 head})=P(\text{All tails})

P=1-\frac{1}{8}

P=\frac{7}{8}

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blagie [28]

Answer:

1st graph: m = -1/2. (m is the slope)

2nd graph: m = 3/2.

3rd graph: Midpoint = (1/2, 1/2)

Step-by-step explanation:

1st graph:

Find the slope by looking for two points on the line. Use the formula m = \frac{y_{2}-y_{1} }{x_{2}-x_{1}}

We can derive the points (-3, 0) and (1, -2). Plug these into the equation above.

m= \frac{-2-0}{1-(-3)}

Simplify this, giving you: m = -1/2.

2nd graph:

Use the same formula as stated above. From this graph, you can plug in the points (-1, 1) and (1, 4)

m = \frac{4-1}{1-(-1)}

Simplifying gets you: m = 3/2.

3rd graph:

To find the midpoint, use the formula: (\frac{x_{1}+x_{2} }{2} , \frac{y_{1} +y_{2} }{2} )

Plug in the end-points of the graph, or (-3, 2) and (4, -1).

You get:

(\frac{-3+4}{2}, \frac{2-1}{2})

Simplify:

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3 0
3 years ago
This robotic arm is made up of two cylinders with equal volume and two triangular prism hands. The volume of each hand is
BaLLatris [955]

Answer:

\frac{r}{3\pi h+r}

Step-by-step explanation:

Since the height isn't given, we assume it to be "h" (of cylinders). And the answer will be in terms of "r" and "h".

The area of 1 arm is given, so the area of 2 arms would be:

A_{arm}=2*(\frac{1}{2}r*\frac{1}{3}r*2r)=\frac{2r^3}{3}

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So, total area is A_arm PLUS A_cyl. The fractional area the arms are would be gotten by taking expression A_arm  divided  by A_total.

Shown below:

\frac{A_{arm}}{A_{total}}=\frac{\frac{2r^3}{3}}{2\pi r^2 h + \frac{2r^3}{3}}

We simplify further:

\frac{\frac{2r^3}{3}}{2\pi r^2 h + \frac{2r^3}{3}}\\=\frac{\frac{2r^3}{3}}{2r^2(\pi h + \frac{r}{3})}\\=\frac{r}{3(\pi h + \frac{r}{3})}\\=\frac{r}{3\pi h+r}

THis is the answer.

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Answer:

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