All categories

3 years ago

The sample space, S, for flipping a fair coin three times is shown

Mathematics

1 answer:

Ksenya-84 [330]3 years ago

3 0

Answer: $\frac{7}{8}$

Step-by-step explanation:

Given

Sample space is $={HHH,THH,HTH,HHT,TTH,THT,HTT,TTT}$

There are 8 element in sample space which indicates the outcome of tossing a coin three times

Probability of obtaining at least one head $=1-P(\text{0 head})$

$P(\text{0 head})=P(\text{All tails})$

$P=1-\frac{1}{8}$

$P=\frac{7}{8}$

You might be interested in

How many boxes to shade if you have 92%

nlexa [21]

How many boxes are there in total?

6 0

2 years ago

The stock of Company A gained 2% today to $79.56. What was the opening price of the stock in the beginning of the day?

CaHeK987 [17]

Answer: $78

Step-by-step explanation:

From the question, we are informed that the stock of Company A gained 2% today to $79.56. The opening price of the stock in the beginning of the day will be calculated as:

= [100% / (100% + 2%)] × 79.56

= (100% / 102%) × 79.56

= 1/1.02 × 79.56

= 79.56/1.02

= 78

Therefore, opening price of the stock in the beginning of the day is $78

5 0

3 years ago

Write (-3, -5) (-1, -19) in point slope form

stiv31 [10]

Answer:

(y + 5) = -7(x + 3)

Step-by-step explanation:

Point Slope Form: (y - y1) = m(x - x1)

<u>Step 1: Find Slope</u>

m = $\frac{y2 - y1}{x2 - x1}$

m = $\frac{-19 - (-5)}{-1 - (-3)}$

m = $\frac{-19 + 5}{-1 + 3}$

m = $\frac{-14}{2}$

m = -7

<u>Step 2: Put into point slope form</u>

Point Slope Form: (y - y1) = m(x - x1)

(y - (-5)) = -7(x - (-3))

(y + 5) = -7(x + 3)

8 0

2 years ago

What is the reason for statement 4 in the two column proof

enot [183]

The reason is the gotter of the right angle is 12

5 0

2 years ago

The curves y = √x and y=(2-x) and the Cartesian axes form two distinct regions in the first quadrant. Find the volumes of rotati

makkiz [27]

Answer:

Step-by-step explanation:

If you graph there would be two different regions. The first one would be

$y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\$

And the second one would be

$y = 2-x \,\,\,\,\,, 1 \leq x \leq 2$ .

If you rotate the first region around the "y" axis you get that

$A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51$

And if you rotate the second region around the "y" axis you get that

$A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188$

And the sum would be 2.51+4.188 = 6.698

If you revolve just the outer curve you get

If you rotate the first region around the x axis you get that

$A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708$

And if you rotate the second region around the x axis you get that

$A_2 = \pi \int\limits_{1}^{2} (2-x)^2 dx = \frac{\pi}{3} = 1.0472$

And the sum would be 1.5708+1.0472 = 2.618

7 0

3 years ago