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2 years ago

Do the products 40×500 and 40 times six hundred have the same number of zeros explain

Mathematics

1 answer:

irina1246 [14]2 years ago

8 0

No because 40 time 500 is 20,000 and 40*600= 24,000

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X2 - 3√3 + 6 = 0 solve by factorisation method

inysia [295]

The answer is 0 I hope that helped

8 0

1 year ago

I don’t understand how to do this

schepotkina [342]

Answer:

The solution is $x =0.$

Step-by-step explanation:

The equation

$\bold{(1).}\: sin(\dfrac{3\pi }{2} +x)+sin(\dfrac{3\pi }{2} +x) =-2$

can be rewritten as

$2* sin(\dfrac{3\pi }{2} +2) =-2$

and can be further simplified to

$sin(\dfrac{3\pi }{2}+x ) =-1$ .

Now, taking the inverse sine of both sides we get:

$sin^{-1}(sin(\dfrac{3\pi }{2} +x) =sin^{-1}(-1)$

$\bold{(2).}\: \dfrac{3\pi }{2} +2 =sin^{-1}(-1)$

The value of the right side on the interval $[0,2\pi)$ is

$sin^{-1}(-1) = \dfrac{3\pi}{2} \: \:( \text{or }270^o)$ ,

which makes the equation (2)

$\dfrac{3\pi }{2}+x =\dfrac{3\pi}{2}$

solving for $x$ gives

$\boxed{x = 0}$

which is our solution.

4 0

2 years ago

F(0)+g(-3) <br><br>I need help ... I need to see if I did the answer correctly

Bezzdna [24]

$f(0)+g(-3)=0^2-2\cdot0+2+1-3\cdot(-3)=3+9=12$

6 0

2 years ago

Esmerelda bought a bag of jelly beans. There were 24 green jelly beans, which made up 8%, percent of all the jelly beans in the

Margarita [4]

So, let's look at the problem once again.

8%, or 8/100 of the bag were green jelly beans.

Let's see what we can do to find out a number of other jelly beans, not including the green ones.

We know that 92% of jelly-beans are not green.

92% is 11.5 times more than 8%
(92/8)

24 (or 8%) times 11.5 = 276

276 - number of jelly beans that are not green.

276 plus 24 = 300.

Answer: 300 jelly beans were in one bag.

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2 years ago

Martha is making a scarf for her sister each day she knits 1/6 of a scarf what fraction of the scarf will be complete after thre

schepotkina [342]

Multiply 1/6 by 3 =1/2
In 3 days she would have completed 1/2 of the scarf.

8 0

2 years ago

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