AB + C
= (x + 1)(x^2 + 2x - 1) + 2x
= x^3 + 2x^2 - x + x^2 + 2x - 1 + 2x
= x^3 + 3x^2 + 3x - 1
Answer:
a = 6
b = 7
Step-by-step explanation:
Since both 36 and 49 are perfect squares, you can find their square roots which are 6 and 7.
To check to see if it is correct, replace the a with 6 and replace the b with 7, then evaluate the exponents.
Answer:d
Step-by-step explanation:
Answer:
Every number is being multiplied by four, so the next number in the sequence should be 1,792
Step-by-step explanation:
Hope this helped!!

where
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.
By continuity of
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, you have
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As

in the numerator, you approach

; in the denominator, you approach

. So you have an indeterminate form
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. Provided the limit indeed exists, L'Hopital's rule can be used.
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Now the numerator approaches

, while the denominator approaches

, suggesting the limit above is 2. This means