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2 years ago

Cuando un poligono puede ser concavo o convexo

Mathematics

1 answer:

Verdich [7]2 years ago

4 0

Para que un polígono sea convexo, todos sus ángulos interiores deben ser inferiores a 180 grados

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A quarter is 1/4 dollar. Noah has 8 quarters. How much money does he have?

Dmitry_Shevchenko [17]

Answer:
noah has $2

step-by-step explanation:
1/4 * 8 = 8/4 = 2

4 0

2 years ago

Why is the answer to this integral's denominator have 1+pi^2

ss7ja [257]

It comes from integrating by parts twice. Let

$I = \displaystyle \int e^n \sin(\pi n) \, dn$

Recall the IBP formula,

$\displaystyle \int u \, dv = uv - \int v \, du$

Let

$u = \sin(\pi n) \implies du = \pi \cos(\pi n) \, dn$

$dv = e^n \, dn \implies v = e^n$

Then

$\displaystyle I = e^n \sin(\pi n) - \pi \int e^n \cos(\pi n) \, dn$

Apply IBP once more, with

$u = \cos(\pi n) \implies du = -\pi \sin(\pi n) \, dn$

$dv = e^n \, dn \implies v = e^n$

Notice that the ∫ v du term contains the original integral, so that

$\displaystyle I = e^n \sin(\pi n) - \pi \left(e^n \cos(\pi n) + \pi \int e^n \sin(\pi n) \, dn\right)$

$\displaystyle I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n - \pi^2 I$

$\displaystyle (1 + \pi^2) I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n$

$\implies \displaystyle I = \frac{\left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n}{1+\pi^2} + C$

6 0

2 years ago

Tim can mow 4 lawns in 6 hours. How many lawn(s) can he mow in 1 hour?

Art [367]

4/6 = 0,66

So, Tim can mow 0,66 lawns in 1 hours.

Control:
0,66 lawns x 6 hours = 4 lawns

6 0

2 years ago

Read 2 more answers

Find the variable in xy=6b

Mkey [24]

Xy=6b
/y . /y
x=6by
that is the answer because there is no true answer

3 0

3 years ago

Read 2 more answers

Please help me again

dangina [55]

Answer:

Step-by-step explanation:

Step 1: Solve for x

x + 3x + 2x = 180

6x / 6 = 180 / 6

x = 30

Step 2: Find the measure of angle C

Angle C = 2x

Angle C = 2(30)

Angle C = 60 degrees

Answer: 60

3 0

3 years ago