Answer:
360$
Step-by-step explanation:
24000× 10%=2400
2400×5%×3=360
Answer:
12
Step-by-step explanation:
The numbers of choices for each of B, C, D are independent of the choices the predecessors have made. It is clear where the car's owners will sit, so all we have to care about is where we put the other people. There are 16−4=12 places left in the cars, so there are 12!
Answer:
right triangle
Step-by-step explanation:
A's x is = 2 and C's x is also 2
A's y is = 1 and B's y is also 1
Answer:
Part a: P (14/30<x<21/30) = 0.1304
Partb: Expected value= Variance= 0.866
Step-by-step explanation:
The poisson distribution is given by
P(x)= μˣ . e^ -u/ x!
In this question
x= 1
n= 30
μ= 1/30
P(x)= μˣ . e^ -u/ x!
= 0.333. e⁻¹/³⁰/1!
= 0.33*0.967/1
= 0.32208
For 2 weeks
x= 14
n= 30
μ= 14/30
P(x)= μˣ . e^ -u/ x!
= 0.467. e⁻¹⁴/³⁰/14!
= 0.467*0.627/14!
= 0.29285/14!
=3.359*e⁻¹²
= 0.0139
For 3 weeks
x= 21
n= 30
μ= 21/30
P(x)= μˣ . e^ -u/ x!
= 0.7* e⁻²¹/³⁰/21!
= 0.7*0.4965/21!
= 0.3476/21!
=6.8037*e⁻²¹
= 0.11648
Part a:
P (14/30<x<21/30) = P (x= 14/30) + P (x=21/30)
(0.0139 +0.11648) =0.1304
Part b:
Probability of Not receiving the call for two weeks = 1- P (x= 14/30)=0.9861
<u><em>The mean and the variance of the Poisson distribution are equal to μ </em></u>
For x= 14
Expected value not getting wrongly dialed phone call in 2 week = μ= 1-14/30 = 1-0.467= 0.533
Variance of not getting wrongly dialed phone call in 2 week= μ=1- 14/30= 1-0.467= 0.533
Expected value of the additional time until the next wrongly dialed phone call
Expected value not getting wrongly dialed phone call in 2 weeks + Expected value of next wrongly dialed phone call in a month
= 0.533+0.33=0.866
Variance of the additional time until the next wrongly dialed phone call
= Expected value of the additional time until the next wrongly dialed phone call =0.866
