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bixtya [17]
3 years ago
13

Find the value of the expression for the given values.

Mathematics
1 answer:
Helen [10]3 years ago
3 0

Answer:

If x= - 2. then 6x - 2 = -14

If x = 6, then 6x - 2 = 34

If x= - 5. then 6x-2= -32

Step-by-step explanation:

You have to substitute the value of x in the expression.

If x = -2,

6x-2 = 6*(-2) - 2 = -12-2 = -14

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Two numbers less than 8 that<br> have 3 as their GCF
Anarel [89]

Answer:

3 and 6

Step-by-step explanation:

GCF's or greatest common factors of numbers 1 to 8

1 : 1

2 : 1, 2

3: 1 , 3

4 : 1, 2, 4

5 : 1, 5

6 : 1, 2, 3, 6

7 : 1, 7

8 : 1, 2, 4, 8

3 and 6 have 3 as their GCF

4 0
2 years ago
Solve the system of equations below by graphing.
AleksandrR [38]
I think it would be B hope it helps
5 0
3 years ago
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arrange the expressions in the correct sequence to rationalize the denominator of the expression -(2)/(\sqrt(x+y-2)-\sqrt(x+y+2)
cupoosta [38]
We have to rationalize the denominator:
\frac{-2}{ \sqrt{x+y-2} - \sqrt{x+y+2} } = \\  \frac{-2}{ \sqrt{x+y-2} -  \sqrt{x+y+2} }* \frac{ \sqrt{x+y-2}+ \sqrt{x+y+2}  }{ \sqrt{x+y-2}+ \sqrt{x+y+2}  }= \\  \frac{-2*( \sqrt{x+y-2}+ \sqrt{x+y+2})  }{x+y-2-(x+y+2)}= \\  \frac{-2*( \sqrt{x+y-2}+ \sqrt{x+y+2})  }{x+y-2-x-y-2}= \\  \frac{-2*( \sqrt{x+y-2}+ \sqrt{x+y+2}  }{-4}= \\  \frac{ \sqrt{x+y-2}+ \sqrt{x+y+2}  }{2}
6 0
2 years ago
Read 2 more answers
"take a number x, double it and then take that result away from 10"<br><br>Write as an expression
Yuki888 [10]

Word Problem:

Take a number, <em>x</em>, double it and then take that result away from 10.

Expression:

10-(2x)

8 0
3 years ago
Use the figure to find the measures of the numbered angles,
Galina-37 [17]

Given:

A figure in which a transversal line t intersect the two parallel lines a and b.

To find:

The measure of the numbered angles.

Solution:

If a transversal line intersect the two parallel lines, then

1. Corresponding angles are equal.

2. Alternate interior angles are equal.

3. Alternate exterior angles are equal.

Now,

m\angle 1+99^\circ=180^\circ              (Linear pair)

m\angle 1=180^\circ-99^\circ

m\angle 1=81^\circ

m\angle 2=99^\circ                         (Vertically opposite angles)

m\angle 3=\angle 1=81^\circ                (Vertically opposite angles)

m\angle 4=99^\circ                         (Corresponding angles)

m\angle 5=\angle 3=81^\circ                (Alternate interior angles)

m\angle 6=99^\circ                         (Alternate exterior angles)

m\angle 7=\angle 3=81^\circ                (Corresponding angles)

Therefore, \angle 1=81^\circ, \angle 2=99^\circ,\angle 3=81^\circ, \angle 4=99^\circ,\angle 5=81^\circ, \angle 6=99^\circ,\angle 7=81^\circ.

8 0
3 years ago
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