Find the value of the expression for the given values.

Mathematics

1 answer:

Helen [10]3 years ago

3 0

Answer:

If x= - 2. then 6x - 2 = -14

If x = 6, then 6x - 2 = 34

If x= - 5. then 6x-2= -32

Step-by-step explanation:

You have to substitute the value of x in the expression.

If x = -2,

6x-2 = 6*(-2) - 2 = -12-2 = -14

You might be interested in

Two numbers less than 8 that have 3 as their GCF

Anarel [89]

Answer:

3 and 6

Step-by-step explanation:

GCF's or greatest common factors of numbers 1 to 8

1 : 1

2 : 1, 2

3: 1 , 3

4 : 1, 2, 4

5 : 1, 5

6 : 1, 2, 3, 6

7 : 1, 7

8 : 1, 2, 4, 8

3 and 6 have 3 as their GCF

4 0

2 years ago

Solve the system of equations below by graphing.

AleksandrR [38]

I think it would be B hope it helps

5 0

3 years ago

Read 2 more answers

arrange the expressions in the correct sequence to rationalize the denominator of the expression -(2)/(\sqrt(x+y-2)-\sqrt(x+y+2)

cupoosta [38]

We have to rationalize the denominator:
$\frac{-2}{ \sqrt{x+y-2} - \sqrt{x+y+2} } = \\ \frac{-2}{ \sqrt{x+y-2} - \sqrt{x+y+2} }* \frac{ \sqrt{x+y-2}+ \sqrt{x+y+2} }{ \sqrt{x+y-2}+ \sqrt{x+y+2} }= \\ \frac{-2*( \sqrt{x+y-2}+ \sqrt{x+y+2}) }{x+y-2-(x+y+2)}= \\ \frac{-2*( \sqrt{x+y-2}+ \sqrt{x+y+2}) }{x+y-2-x-y-2}= \\ \frac{-2*( \sqrt{x+y-2}+ \sqrt{x+y+2} }{-4}= \\ \frac{ \sqrt{x+y-2}+ \sqrt{x+y+2} }{2}$