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Svet_ta [14]
3 years ago
6

Emma works in a department store selling

Mathematics
1 answer:
Monica [59]3 years ago
4 0

Answer:253.33...

Step-by-step explanation:

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A student started out poorly on his first mathematics test. However, he doubled his score on each of the next two tests. The thi
dsp73
His score is 50

How to:
First test grade:0
Second test grade:50
Third test grade: 100
Add all three and divide by 3
6 0
2 years ago
El valor de *x* en la operación de -4+2x=0?​
Vesnalui [34]
Add 4 to both sides to isolate the variable (-4+4=0) (2x+0=2x) (0+4=4) which leaves you with 2x=4 divide both sides by 2 to get rid of the number in front of the variable to get x by itself (2x/2=x) (4/2=2) therefore you’re left with x=2 (lo siento yo no hablo español la respuesta es x=2)

6 0
3 years ago
HELP ASAP ...........
dedylja [7]

Answer:

A

Step-by-step explanation:

Given

y - 2x - 8 = 0 ( add 2x + 8 to both sides )

y = 2x + 8 → (1)

y² + 8x = 0 → (2)

Substitute y = 2x + 8 into (2)

(2x + 8)² + 8x = 0 ← expand left side using FOIL and simplify

4x² + 32x + 64 + 8x = 0

4x² + 40x + 64 = 0 ( divide through by 4 )

x² + 10x + 16 = 0 ← in standard form

(x + 8)(x + 2) = 0 ← in factored form

x + 8 = 0 ⇒ x = - 8

x + 2 = 0 ⇒ x = - 2

Substitute these values into (1) for corresponding values of y

x = - 8 : y = 2(- 8) + 8 = - 16 + 8 = - 8 ⇒ P (- 8, - 8)

x = - 2 : y = 2(- 2) + 8 = - 4 + 8 = 4 ⇒ Q (- 2, 4 )

Calculate the length of PQ using the distance formula

PQ = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = P (- 8, - 8) and (x₂, y₂ ) = Q (- 2, 4 )

PQ = \sqrt{(-2-(-8))^2+(4-(-8))^2}

      = \sqrt{(-2+8)^2+(4+8)^2}

       = \sqrt{6^2+12^2}

       = \sqrt{36+144}

       = \sqrt{180}

       = \sqrt{36(5)}

       = \sqrt{36} × \sqrt{5}

        = 6\sqrt{5} → A

8 0
2 years ago
-2 x (-7) = <br> 24 divided by (-3) =
juin [17]

Answer:

1)  14

2) -8

Step-by-step explanation:

-2 × (-7) = 14

24 ÷ (-3) = -8

5 0
3 years ago
NEED ANSWER ASAP WILL GIVE THANKS + BRAINLIEST
il63 [147K]

\\ \sf\longmapsto f(x)=2x^2-3x+1

\\ \sf\longmapsto f(1)=2(1)^2-3(1)+1

\\ \sf\longmapsto f(1)=2(1)-3+1

\\ \sf\longmapsto f(1)=0

Now

\\ \sf\longmapsto f(2)=2(2)^2-3(2)+1

\\ \sf\longmapsto f(2)=2(4)-6+1

\\ \sf\longmapsto f(2)=8-5

\\ \sf\longmapsto f(2)=3

4 0
2 years ago
Read 2 more answers
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