The distance from point (15,-21) to the line 5x + 2y = 4 is 27.5 units
Given the coordinate (15, -21) and the line 5x + 2y = 4
In order to get the point on the line 5x + 2y =4, we can a point on the line
Let x = 0
5(0) + 2y = 4
2y = 4
y = 2
The point (0, 2) is on the line.
Find the distance between the point (15, -21) and (0, 2) using the distance formula
Hence the distance from point (15,-21) to the line 5x + 2y = 4 is 27.5 units
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(x,y)→(x+a,y+b).
Then the function is
2. Reflection across the y-axis acts in following way:
(x,y)→(-x,y).
Then the function is
3. Reflection across the x-axis acts in following way:
(x,y)→(x,-y).
Then the function is
4. Rotation of 90 degrees counterclockwise about the origin, point O acts bu the rule:
(x,y)→(-y,x).
Then the function is
5. Rotation of 180 degrees counterclockwise about the origin, point O acts bu the rule:
(x,y)→(-x,-y).
Then the function is
6. Rotation of 270 degrees counterclockwise about the origin, point O acts bu the rule:
(x,y)→(y,-x).
Then the function is