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Bogdan [553]
3 years ago
15

Using the quadratic formula to solve 7x2 – x = 7, what are the values of x?

Mathematics
2 answers:
lesya692 [45]3 years ago
7 0

Answer:c

Step-by-step explanation:

Kruka [31]3 years ago
5 0
How the quadratic formula works:

For any quadratic equation ax² + bx + c = 0, the solution is x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.

In the case of our equation 7x² - x = 7, first we need to subtract 7 from each side so that we have 0 on the right.
7x² - x - 7 = 0

Identify the values of a, b, and c.
a = 7, b = -1, and c = -7.

Plug these into our quadratic formula and solve.

x=\frac{-(-1)\pm\sqrt{(-1)^2-4(7)(-7)}}{2(7)}=\boxed{\frac{1\pm\sqrt{197}}{14}

There are two values for x: (1+√197)/14 and (1-√197)/14.
The approximate values for these are 1.073976 and -0.931119.
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Sliva [168]

Hello and Good Morning/Afternoon

<u>Let's take this problem step by step.</u>

        5=\frac{1}{3}(5x-15)\\ 5=\frac{5}{3}x-5\\ 5+5= \frac{5}{3}x-5 +5\\10=\frac{5}{3}x\\ 10 * 3 = 3* \frac{5}{3}x\\30=5x\\\frac{30}{5} =\frac{5}{5}x\\ 6=x\\x=6

<u>What did we do in this problem</u>

  • we ensured that both sides remained equally balanced in value
  • took everything step-by-step to make sure that there were no mistakes
  • to check it, we can plug it back into the original equation to see if it works

                  5=\frac{1}{3}(5(6)-15)\\ 5=\frac{1}{3} (30-15)\\5=\frac{1}{3}*15\\ 5=5 \checkmark\\

<u>Answer: x = 6</u>

Hope that helps!

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