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Bogdan [553]
4 years ago
15

Using the quadratic formula to solve 7x2 – x = 7, what are the values of x?

Mathematics
2 answers:
lesya692 [45]4 years ago
7 0

Answer:c

Step-by-step explanation:

Kruka [31]4 years ago
5 0
How the quadratic formula works:

For any quadratic equation ax² + bx + c = 0, the solution is x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.

In the case of our equation 7x² - x = 7, first we need to subtract 7 from each side so that we have 0 on the right.
7x² - x - 7 = 0

Identify the values of a, b, and c.
a = 7, b = -1, and c = -7.

Plug these into our quadratic formula and solve.

x=\frac{-(-1)\pm\sqrt{(-1)^2-4(7)(-7)}}{2(7)}=\boxed{\frac{1\pm\sqrt{197}}{14}

There are two values for x: (1+√197)/14 and (1-√197)/14.
The approximate values for these are 1.073976 and -0.931119.
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Let gbe a function such that g(x) = -2r + 5 and is defined on the domain (-1,3) State the range of this function in interval not
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Answer:

The range interval is: (7, -1)

Step-by-step explanation:

Given the function

g(x) = -2r+5

  • As the domain is (-1, 3)

Let us put the domain values in the interval (-1, 3)

Putting x = -1

g(x)=-2r+5

      = -2(-1)+5

      = 2+5

      = 7

Putting x = 0

g(x)=-2r+5

      = -2(0)+5

      =0+5

      = 5

Putting x = 1

g(x)=-2r+5

      = -2(1)+5

      =-2+5

      = 3

Putting x = 2

g(x)=-2r+5

      = -2(2)+5

      =-4+5

      = 1

Putting x = 3

g(x)=-2r+5

      = -2(3)+5

      =-6+5

      = -1

Thus the range interval is: (7, -1)

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4 years ago
3x+2y-5z=-1<br> 4x-3y+2z=-13<br> 2x-5y+4z=-9
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2.3x+6y=15
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3x+6y=15
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3.7y = -14x + 42 
<span>7y = 14 x + 14

-14x+42=14x+14
-28x=-28
x=1</span>
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3 years ago
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