Ask question

Ask question

All categories

Bad White [126]

3 years ago

8

6( 5-8x) +12= -54

2 answers:

UkoKoshka [18]3 years ago

5 0

<span>6( 5-8x) +12= -54
30-48x+12=-54 this comes from distributing(multiplying) 6x5 and 6 times -8x
30+12-48x=-54 you have to add the coefficients 30+12
42-48x=-54
-42 -42
-----------------------
-48x=-96 divide by -48
x=2</span>

natita [175]3 years ago

4 0

You use the distributive property by distributing the 6 to 5 and -8x which gives you 30-48x+12=-54 then you subtract 30 and 12 from both sides to get -96 then divide by -48 to solve for x which gives you 2

You might be interested in

PLEASE HELP ME GUYSS!!!

Assoli18 [71]

Answer:

.......................................

3 0

2 years ago

Jc bent 26.32 on 8 gallons of gas how much wood he spend for 20

dedylja [7]

1) divide 26.32 by 8 = 3.29
2) 3.29 x 20= 65.80
3) he would spend 65.80 on 20 gallons of gas

4 0

2 years ago

X^2 + y^2=40 and y=x-4 solve this simultaneous equation

inn [45]

Write x-4 instead of y.
x²+(x-4)²=40
x²+x²-8x+16=40
2x²-8x-24=0
x²-4x-12=0
(x-6)(x+2)=0
x=6 or x=-2

for x=6, y=6-4 = 2
for x=-2, y=-2-4 = -6

3 0

3 years ago

Kirans aunt is 15 years older than kiran. how old will kirans aunt be when kiran is 13?

Leya [2.2K]

Answer:

28 will be your answer!

Step-by-step explanation:

I don't properly know how to explain thia but i know its the answer

8 0

2 years ago

Read 2 more answers

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th

mash [69]

Answer:

The rocket hits the gorund after approximately 10.71 seconds.

Step-by-step explanation:

The height of the rocket <em>y</em> in feet <em>x</em> seconds after launch is given by the equation:

$y=-16x^2+165x+69$

And we want to find the time in which the rocket will hit the ground.

When it hits the ground, its height above ground will be 0. Hence, we can let <em>y</em> = 0 and solve for <em>x: </em>

<em /> $0=-16x^2+165x+69$ <em />

We can use the quadratic formula:

$\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

In this case, <em>a</em> = -16, <em>b</em> = 165, and <em>c </em>= 69.

Substitute:

$\displaystyle x=\frac{-165\pm\sqrt{(165)^2-4(-16)(69)}}{2(-16)}$

Evaluate:

$\displaystyle x=\frac{-165\pm\sqrt{31641}}{-32}=\frac{165\pm\sqrt{31641}}{32}$

Hence, our solutions are:

$\displaystyle x_1=\frac{165+\sqrt{31641}}{32}\approx 10.71\text{ or } x_2=\frac{165-\sqrt{31641}}{32}\approx-0.40$

Since time cannot be negative, we can ignore the first answer.

So, the rocket hits the gorund after approximately 10.71 seconds.

7 0

2 years ago