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3 years ago

Please help me figure this out

Mathematics

1 answer:

Lelechka [254]3 years ago

7 0

142 easy peasy. This is an easy one

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what is one clue that lets you know that a math problem requires you to do a two steps multi problem?

elena55 [62]

Answer:

If there are more than one thing on the x. Let me just show you because I can't really explain it very well, so I'm sorry.

Step-by-step explanation:

5x+23=10

23(x^2)+5=27

There is more than one thing acting on the x to get it into a number.

6 0

4 years ago

Find the vertical asymptote(s) of f of x equals quantity 5 x squared plus 3x plus 6 end quantity over quantity x squared minus 1

natka813 [3]

Answer:

x = 10 and x = -10

Step-by-step explanation:

Given the function

$f(x)=\dfrac{5x^2+3x+6}{x^2-100}$

This function is undefied when the denominator equals to 0. Find these values for x:

$x^2-100=0\\ \\(x-10)(x+10)=0\\ \\x-10=0\ \ \text{or}\ \ x+10=0\\ \\x=10\ \ \text{or}\ \ x=-10$

This means that vertical lines x = 10 and x = -10 are vertical asymptotes (the graph of the function f(x) cannot meet these lines because this function is undefined at x = 10 and x = -10)

7 0

3 years ago

A square has an area of 81x square cm. What is the perimeter of the square ?

Fudgin [204]

Answer:

The perimeter of the square is $36\sqrt{x}\ cm$

Step-by-step explanation:

step 1

Find the length side of the square

we know that

The area of a square is equal to

$A=b^{2}$

where

b is the length side of the square

we have

$A=81x\ cm^{2}$

substitute and solve for b

$81x=b^{2}$

square root both sides

$b=9\sqrt{x}\ cm$

step 2

Find the perimeter of the square

we know that

The perimeter of the square is equal to

$P=4b$

we have

$b=9\sqrt{x}\ cm$

substitute

$P=(4)9\sqrt{x}$

$P=36\sqrt{x}\ cm$

6 0

3 years ago

Find the equation of the line through the points (6, -9) and (-2, -1).

slava [35]

Answer:

y = -1x - 3

Step-by-step explanation:

y2 - y1 / x2 - x1

-1 - (-9) / -2 - 6

8/-8

= -1

y = -1x + b

-1 = -1(-2) + b

-1 = 2 + b

-3 = b

5 0

3 years ago

Can someone solve this

zysi [14]

You know how Soh Cah Toa applies to right triangles; you can assign the adjacent side = 4 and hypotenuse = 7

CosФ = (adjacent) / (hypotenuse)

Then with the Pythagorean theorem
4² + b² = 7²
16 + b² = 49
b² = 49 - 16
b² = 33
b = √(33)

So "b" is the opposite side.

SinФ = (opposite) / (hypotenuse) = √(33)/7
TanФ = (opposite) / (adjacent) = √(33)/4

3 0

4 years ago