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irakobra [83]
3 years ago
6

Write an integer for each situation.

Mathematics
1 answer:
yawa3891 [41]3 years ago
6 0
Integer is an any number which can be negative number, positive number or zero. It is not a fractional number.
<span>In deposit of $90 an integer is +90
In case of 45 seconds before launch an integer is -45
In 580 B.C. -580 is the integer 
In an elevation of 3,400 ft, +3400 is an integer</span>
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John runs a computer software store. Yesterday he counted 123 people who walked by the store, 56 of whom came into the store. Of
vaieri [72.5K]

Answer:

a) There is a 45.53% probability that a person who walks by the store will enter the store.

b) There is a 41.07% probability that a person who walks into the store will buy something.

c) There is a 18.70% probability that a person who walks by the store will come in and buy something.

d) There is a 58.93% probability that a person who comes into the store will buy nothing.

Step-by-step explanation:

This a probability problem.

The probability formula is given by:

P = \frac{D}{T}

In which P is the probability, D is the number of desired outcomes and T is the number of total outcomes.

The problem states that:

123 people walked by the store.

56 people came into the store.

23 bought something in the store.

(a) Estimate the probability that a person who walks by the store will enter the store.

123 people walked by the store and 56 entered the store, so T = 123, D = 56.

So

P = \frac{D}{T} = \frac{56}{123} = 0.4553

There is a 45.53% probability that a person who walks by the store will enter the store.

(b) Estimate the probability that a person who walks into the store will buy something.

56 people came into the store and 23 bought something, so T = 56, D = 23.

So

P = \frac{D}{T} = \frac{23}{56} = 0.4107

There is a 41.07% probability that a person who walks into the store will buy something.

(c) Estimate the probability that a person who walks by the store will come in and buy something.

123 people walked by the store and 23 came in and bought something, so T = 123, D = 23.

So

P = \frac{D}{T} = \frac{23}{123} = 0.1870

There is a 18.70% probability that a person who walks by the store will come in and buy something.

(d) Estimate the probability that a person who comes into the store will buy nothing.

Of the 56 people whom came into the store, 23 bought something. This means that 56-23 = 33 of them did not buy anything. So:

D = 33, T = 56

P = \frac{D}{T} = \frac{33}{56} = 0.5893

There is a 58.93% probability that a person who comes into the store will buy nothing.

8 0
3 years ago
Pleaseeeeeeeeeeeee need help
bagirrra123 [75]
The answer is 35
i know this because the side is 5 and the other side is 7 
so if you multiply 5 time 7 it will equal 35
8 0
3 years ago
Roger will flip a coin 3 times. Which 2 events are disjoint?
Ganezh [65]

Answer: D. Getting at least 2 heads and Getting at least 2 tails

=========================================================

Explanation:

Choice A is not disjoint because "getting at least 1 tail" could have the sequence TTH. We see that we have two tails and exactly one head. So the events "getting exactly 1 head" and "Getting at least 1 tail" are possible to occur at the same time; therefore, they aren't disjoint events. Disjoint events are two events that cannot occur simultaneously. An example would be flipping heads and tails on the same coin at the same time.

Choice B is also not disjoint. We could have the sequence THT, which has at least one head and at least one tail. "At least" means that amount or more.

Choice C is also not disjoint. We could have the sequence HTT. This has exactly one head and at least two tails.

Choice D is the only thing left. It must be the answer. It is not possible to get 2 heads and 2 tails when Roger only flips the coin 3 times. He would need to flip the coin at least 4 times for this to happen. The portions "at least" don't even need to be considered. So this shows how choice D is disjoint.

7 0
3 years ago
6. In the following right angled triangles, find the unknown sizes of the acute angles. Which no you can do plz do it .​
Sedaia [141]

Answer:

Here's for you...........

8 0
3 years ago
Tracy sells water at a fair in 17oz bottles or 11oz cans. If on one shelf she has 11 containers of water that hold a total of 15
blondinia [14]

Answer:

Number of bottles = 6

Number of cans = c

Step-by-step explanation:

Given that:

Container for selling water :

17 oz bottle

11 oz can

Let number of bottles = b

Number of cans = c

b + c = 11 - - - (1)

17b + 11c = 157 - - - (2)

b = 11 - c

Substitute into (2)

17(11 - c) + 11c = 157

187 - 17c + 11c = 157

187 - 6c = 157

-6c = 157 - 187

-6c = -30

c = 30/6

c = 5

From ; b = 11 - c

b = 11 - 5

b = 6

Hence,

Number of bottles = 6

Number of cans = c

3 0
3 years ago
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