Answer:
The value is 
Explanation:
From the question we are told that
The mass of the block is 
The force constant of the spring is 
The amplitude is 
The time consider is 
Generally the angular velocity of this block is mathematically represented as

=> 
=> 
Given that the block undergoes simple harmonic motion the velocity is mathematically represented as

=> 
=> 
Answer:
Explanation:
Height attained by body = 50 cm
= .5 m
Initial velocity = u
v² = u² - 2gh
0 = u² - 2gh
u² = 2 x 9.8 x .5
u = 3.13 m /s
During the initial period , the muscle stretches by around 10 cm during which force by ground reacts on the body and gives acceleration to achieve velocity of 3.13 m/s from zero .
v² = u² + 2as
3.13² = 0 + 2 a x .10
a = 49 m/s²
reaction by ground R
Net force
R-mg = ma
R= m ( g +a )
= mg + ma
=W + (W/g) x a
W ( 1 + a / g )
= W ( 1 + 49 / 9.8 )
= 6W
Explanation:
1. W = F x D
F = W/D
F = 120/6 = 20Newton
2. P. E = mgh
P. E = 1.5x10x2 = 30Joules
3. It means that the energy the body possesses at that point is 20Joules
Answer:
.05
Explanation:
wavelength/frequency = wave speed
45 = 2.5/x
x = 0.05
Answer:
376966.991 Joules
Explanation:
Given that :
the height = 12 m
Let assume the tank have a thickness = dh
The radius of the tank by using the concept of similar triangle is :


The area of the tank =
The area of the tank = 
The area of the tank = 
The volume of the tank is = area × thickness
= 
Weight of the element = 
where;
= density of water ; which is given as 10000 N/m³
So;
Weight of the element = 
Weight of the element = 
However; the work required to pump this water = weight × height rise
where the height rise = 12 - h
the work required to pump this water =
(12 - h)
the work required to pump this water = 
We can determine the total workdone by integrating the work required to pump this water
SO;
Workdone = 
= 
= ![\mathbf{ 69.44 \pi[ \frac{12h^3}{3}- \frac{h^4}{4}]^{12}}_0} }](https://tex.z-dn.net/?f=%5Cmathbf%7B%2069.44%20%5Cpi%5B%20%5Cfrac%7B12h%5E3%7D%7B3%7D-%20%20%5Cfrac%7Bh%5E4%7D%7B4%7D%5D%5E%7B12%7D%7D_0%7D%20%7D)
= ![\mathbf{69.44 \pi [ \frac{12^4}{3}-\frac{12^4}{4}]}](https://tex.z-dn.net/?f=%5Cmathbf%7B69.44%20%5Cpi%20%5B%20%5Cfrac%7B12%5E4%7D%7B3%7D-%5Cfrac%7B12%5E4%7D%7B4%7D%5D%7D)
= ![\mathbf{69.44 \pi*12^4 [ \frac{4-3}{12}]}](https://tex.z-dn.net/?f=%5Cmathbf%7B69.44%20%5Cpi%2A12%5E4%20%5B%20%5Cfrac%7B4-3%7D%7B12%7D%5D%7D)
= 
= 376966.991 Joules