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faust18 [17]
3 years ago
14

Forcé vs mass graph slope

Physics
1 answer:
maksim [4K]3 years ago
5 0

The slope of a force vs mass graph is equal to the acceleration.

Explanation:

We can answer this question by using Newton's second law, which states that:

F=ma (1)

where:

F is the net force on an object

m is the mass of the object

a is its acceleration

We notice that if we plot a graph of force vs mass,

- The mass corresponds to the x-variable

- The force corresponds to the y-variable

For a straight line passing through the origin, the equation is

y=mx (2)

Where m is the slope of the line. We notice that eq.(1) and (2) are identical if we replace x with m (mass) and y with F (force): therefore, the slope m corresponds to the acceleration, a.

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

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A composite load consists of three loads connected in parallel. One draws 100 W at a PF of 0.92 lagging, another takes 250 W at
fenix001 [56]

Answer:

a) I_{RMS} = 4.79 A

b) PF = 0.908

Explanation:

Get the reactive powers for each of the loads:

Reactive power = Real Power * tanθ

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Power factor, cos \theta_{1} = 0.92

\theta_{1} = cos^{-1} 0.92\\\theta_{1} = 23.074

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Active power, P₂ = 250 W

Power factor, cos \theta_{2} = 0.8

\theta_{2} = cos^{-1} 0.8\\\theta_{2} = 36.87

Q_{2}= P_{1} tan \theta_{2} \\Q_{2}= 250tan 36.87\\Q_{2}= 187.5 W

For load 3

Active power, P₃ = 250 W

Power factor, cos \theta_{3} = 1

\theta_{3} = cos^{-1} 1\\\theta_{3} =0

Q_{2}= P_{1} tan \theta_{3} \\Q_{3}= 150tan 0\\Q_{3}= 0 W

Calculate the total reactive power, Q_{net} = 42.6 + 187.5 + 0

Q_{net} = 230.1 W

Calculate the total active power, P_{net} = 100 + 250 + 150 = 500 W

S_{net} = P_{net} + Q_{net} \\S_{net} = 500 + j230.1

P_{net} = IVcos \theta_{net}

\theta_{net} = tan^{-1} \frac{230.1}{500} \\\theta_{net} = 24.712

V = 115 V_{rms}

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b) Power factor of the composite load is cos\theta_{net}

\theta_{net}  = 24.712\\PF = cos 24.712\\PF = 0.908

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