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sergejj [24]
3 years ago
11

HELP PLS MARKING BRANLIST 100 Pts TAKING TEST RN

Physics
1 answer:
vredina [299]3 years ago
5 0

Answer:

0.5 m/s2

Explanation:

accelration formula : final velocty - starting velocity divided by time

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How does an atom change if all of its electrons are removed?
Alex
<span>The atom becomes positively charged.

When you add electrons to a neutral atom, it is no longer a neutral atom, it has a negative change and is an anion. When you take away electrons from a neutral atom, it is no longer a neutral atom- it becomes a positive atom, and is a cation.</span>


6 0
3 years ago
Tenses of<br>write=<br>read=<br><br>​
PilotLPTM [1.2K]

Answer:

present

Explanation:

read doesn't change but write is in present tense

7 0
3 years ago
Which statement is correct?
Sedbober [7]

Answer:

The answer is "Choice C ".

Explanation:

The relationship between the E and V can be defined as follows:

\to E= -\Delta V

Let,

\to E= \frac{\delta V}{\delta x}

When E=0

\to   \frac{\delta V}{\delta x}=0

v is a constant value

Therefore, In the electric potential in a region is a constant value then the electric-field must be into zero that is everywhere in the given region, that's why in this question the "choice c" is correct.

7 0
3 years ago
HeLp AsAp!!!!!! How long would it take you to hop 30 meters based on your speed for the 5-meter trial? Show your work!
Novosadov [1.4K]

Answer:

20.5s

Explanation:

Given parameters:

Distance = 30m

Unknown:

Time  = ?

Solution:

The time it will take to hop a distance of 30m using the speed for the 5m trial is the duration of the trip.

 The speed for the 5m trial  = 1.46m/s

Now;

    Speed  = \frac{distance}{time}

      Distance = speed x time

      time  = \frac{distance }{speed}

Input the parameters and solve;

     time  = \frac{30}{1.46}   = 20.5s

7 0
3 years ago
After being struck by a bowling ball, a 1.3 kg bowling pin sliding to the right at 5.0 m/s collides head-on with another 1.3 kg
GuDViN [60]

Answer:

a) 4.2m/s

b) 5.0m/s

Explanation:

This problem is solved using the principle of conservation of linear momentum which states that in a closed system of colliding bodies, the sum of the total momenta before collision is equal to the sum of the total momenta after collision.

The problem is also an illustration of elastic collision where there is no loss in kinetic energy.

Equation (1) is a mathematical representation of the the principle of conservation of linear momentum for two colliding bodies of masses m_1 and m_2 whose respective velocities before collision are u_1 and u_2;

m_1u_1+m_2u_2=m_1v_1+m_2v_2..............(1)

where v_1 and v_2 are their respective velocities after collision.

Given;

m_1=1.3kg\\u_1=5m/s\\m_2=1.3kg\\u_2=0m/s

Note that u_2=0 because the second mass m_2 was at rest before the collision.

Also, since the two masses are equal, we can say that m_1=m_2=m so that equation (1) is reduced as follows;

mu_1+mu_2=mv_1+mv_2\\\\m(u_1+u_2)=m(v_1+v_2)..............(2)

m cancels out of both sides of equation (2), and we obtain the following;

u_1+u_2=v_1+v_2.............(3)

a) When v_1=0.8m/s, we obtain the following by equation(3)

5+0=0.8+v_2\\hence\\v_2=5-0.8\\v_2=4.2m/s

b) As m_1 stops moving v_1=0, therefore,

5+0=0+v_2\\v_2=5m/s

5 0
3 years ago
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