The fraction that should be removed is 1/5.
<h3>How to calculate the fraction?</h3>
It should be noted that from the information, 40% of the coins are 20-cent coins and the rest are 50-cent coins. Those that are 50 cent will be:
= 100 - 40%
= 60%
The fraction that's should be removed will be:
= 2/5 - x = 1/5
x = 2/5 - 1/5
x = 1/5
The fraction that should be removed is 1/5.
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Let's simplify step-by-step To understand :)
3x2−7x−(x2+3x−9)
Distribute the Negative Sign:
=3x2−7x+−1(x2+3x−9)
=3x2+−7x+−1x2+−1(3x)+(−1)(−9)
=3x2+−7x+−x2+−3x+9
Combine Like Terms:)
=3x2+−7x+−x2+−3x+9
=(3x2+−x2)+(−7x+−3x)+(9)
=2x2+−10x+9
Answer :)
=2x2−10x+9
HOPE THIS HELPS
<h2>(1)</h2><h2> =(a+b)(3c-d)</h2><h2> =a(3c-d)+b(3c-d)</h2><h2> =3ac-ad+3bc-bd</h2>
<h2>(2)</h2><h2> =(a-b)(c+2d)</h2><h2> =a(c+2d)-b(c+2d)</h2><h2> =ac+2ad-bc-2bd</h2>
<h2>(3)</h2><h2> =(a-b)(c-2d)</h2><h2> =a(c-2d)-b(c-2d)</h2><h2> =ac-2ad-bc+2bd</h2>
<h2>(4)</h2><h2> =(2a+b)(c-3d)</h2><h2> =2a(c-3d)+b(c-3d)</h2><h2> =2ac-6ad+bc-3bd</h2>
Answer:
B: Y=1/2×+2 I think that's it
The sin A is equal to 12/13 and the tan (A) is equal to 12/5.
<h3>RIGHT TRIANGLE</h3>
A triangle is classified as a right triangle when it presents one of your angles equal to 90º. The greatest side of a right triangle is called hypotenuse. And, the other two sides are called cathetus or legs.
The math tools applied for finding angles or sides in a right triangle are the trigonometric ratios or the Pythagorean Theorem.
The Pythagorean Theorem says:
. And the main trigonometric ratios are:

The question gives cos (A)=5/13. If cos (A) is represented by the quotient between the adjacent leg and the hypotenuse, you have:
adjacent leg=5
hypotenuse=13
Therefore, you can find the opposite leg of A from Pythagorean Theorem, see below.

Thus, the opposite leg is equal to 12. Now, you can find sin (A) since:

Finally, you can find the tan (A) since:

Learn more about trigonometric ratios here:
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