All categories

3 years ago

Solve for y in terms of x. 4xy-3y=12

Mathematics

1 answer:

Anestetic [448]3 years ago

5 0

4xy-3y=12
y(4x-3)=12
y=12/(4x-3)

You might be interested in

Please someone help me

Yuki888 [10]

Answer: H

Step-by-step explanation:

We can see this rectangular prism will have side lengths of 5, 3, 7.

So we can use the fact Surface Area = 2(lh+wh+lw) to get:

2(15 + 35 + 21) = 2(71) = 142

5 0

2 years ago

3/4 W + 8 = 1/3 w – 7

Montano1993 [528]

Answer:

Step-by-step explanation:

$\dfrac{3}{4}W+8=\dfrac{1}{3}W-7\qquad\text{subtract 8 from both sides}\\\\\dfrac{3}{4}W+8-8=\dfrac{1}{3}W-7-8\\\\\dfrac{3}{4}W=\dfrac{1}{3}W-15\qquad\text{multiply both sides by}\ LCM(4,\ 3)=12\\\\12\!\!\!\!\!\diagup^3\cdot\dfrac{3}{4\!\!\!\!\diagup_1}W=12\!\!\!\!\!\diagup^4\cdot\dfrac{1}{3\!\!\!\!\diagup_1}W-(12)(15)\\\\(3)(3W)=(4)(1W)-180\\\\9W=4W-180\qquad\text{subtract}\ 4W\ \text{from both sides}\\\\9W-4W=4W-4W-180\\\\5W=-180\qquad\text{divide both sides by 5}\\\\\dfrac{5W}{5}=\dfrac{-180}{5}\\\\W=-36$

7 0

2 years ago

What is the reciprocal of 5/7

Ahat [919]

7/5 is the reciprocal

4 0

2 years ago

Read 2 more answers

Note: The square is not drawn to scale.<br><br> What is the area of the square above?

Nataliya [291]

Answer:

where is the square at I cannot see it

6 0

2 years ago

A genetic experiment involving peas yielded one sample of offspring consisting of 430 green peas and 155 yellow peas. Use a 0.05

Dimas [21]

Answer:

the null and alternative hypothesis are

$H_{0}$ : p=0.24

$H_{a}$ : p≠0.24

Test statistic is 1.416.

P-Value is 0.1568

We fail to reject the null hypothesis under 0.05 significance level

<em>At 0.05 significance</em> we cannot say that the proportion of offspring peas will be yellow is not 0.24 (24%)

Step-by-step explanation:

Let p be the proportion of offspring peas will be yellow. Then,

$H_{0}$ : p=0.24

$H_{a}$ : p≠0.24

test statistic can be calculated as

z= $\frac{p(s)-p}{\sqrt{\frac{p*(1-p)}{N} } }$ where

p(s) is the sample proportion of yellow offspring peas ( $\frac{155}{155+430} =0.265$
p is the proportion of yellow offspring peas assumed under null hypothesis. (0.24)

N is the sample size (585)

Test statistic is z= $\frac{0.265-0.24}{\sqrt{\frac{0.24*0.76}{585} } }$ ≈ 1.416.

Using z-table, we can find that P-Value is 0.1568

We fail to reject the null hypothesis under 0.05 significance level since 0.157>0.05

We can conclude that <em>at 0.05 significance</em> we cannot say that the proportion of offspring peas will be yellow is not 0.24 (24%)

6 0

3 years ago