The circumference of the outer edge of the path around the pool is 113.04 ft.
<h3>
What is the circumference?</h3>
The Circumference (or) perimeter of circle = 2πR. where, R is the radius of the circle.
Given
A circular swimming pool has a radius of 15 ft.
There is a path all the way around that pool that is three feet wide.
A circle has a radius of 15 feet.
A larger circle goes around the smaller circle that is 3 feet wide.
The radius of the outer edge of the path around the pool = Radius of circle + width of outer circle.
The radius of the outer edge of the path around the pool = 15 + 3
The radius of the outer edge of the path around the pool = 18ft
The circumference of the outer edge of the path around the pool is;

Hence, the circumference of the outer edge of the path around the pool is 113.04 ft.
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brainly.com/question/5023328
Answer:
m
Step-by-step explanation:
Square area: m²
The formula for finding the square area: m×m=m²
m²=√(m²)=m
one side of the square is equal to m
Answer:
30
Step-by-step explanation:
Each one has 10 tenths, so 3 ones have 30 tenths.
You can do this by dividing 3 by 1/10.
3/(1/10) = 3/1 * 10/1 = 30/1 = 30
Answer:
50/7.
Simplified to 7.14.
Step-by-step explanation:
Combine like terms, 5x and 9x.
5x+9x=14x
14x = 100
14x / 14 = 100 / 14
x = 50/7 or 7.14
Hope this helps!
Step-by-step explanation:
Since ∠E is right angle, its opposite side is DF and the legs are DE and EF.
<u>Pythagorean applied:</u>