f(x) being even means
f(x) = f(-x)
So the zeros come in positive and negative pairs. If there are an odd number of intercepts like there are here, it's because one of them is x=0 which is its own negation.
Given zero x=6 we know x=-6 is also a zero.
So we know three zeros, and know the other two zeros are a positive and negative pair.
The only choice with (-6,0) and (0,0) is A.
Choice A
Answer:
(5,-6)
Step-by-step explanation:
This is where the two lines meet. I hope this helps ◕ ◡ ◕
Steps to solve:
g(x) = – x^2 + 4x + 3 when g(-3).
~Substitute x with -3.
g(-3) = -(-3)^2 + 4(-3) + 3
~Simplify
g(-3) = -9 - 12 + 3
~Simplify using PEMDAS
g(-3) = -18
Best of Luck!
Answer:
The enlargement will be 25 times and the enlargement area will be 
.
Step-by-step explanation:
It is given that each grid unit is equal to 3 inches. SO we have to use this scale.
The total height of the scale drawing is 21 inch and the enlargement has a height given as 105 inches. Therefore it has scale factor of 5. It means that each dimension is enlarged by 5 times the dimension in the scale drawing. So the enlargement of the logo will be 25 times and the enlargement area will be 2250 square inches.
In order to solve this, we must find out how many times 7 goes into 80. We can do this by either subtracting individual 7s from 80, or by adding 7s together until we cannot add another without going past 80.
For this answer, I will use the addition method.
7 + 7 = 14
14 + 7 = 21
21 + 7 = 28
28 + 7 = 35
35 + 7 = 42
42 + 7 = 49
49 + 7 = 56
56 + 7 = 63
63 + 7 = 70
70 + 7 = 77
From 77, we cannot add another 7 to it without going over 80, since 77 + 7 = 84.
So, let's count the sevens that we have added up so far, and when we do, we can see that there are 11 of them, adding up to 77.
So 7 goes into 80 11 times. Now, let's find the remainder...
To find the remainder, you just need to subtract the final added number from the number you are dividing from.
80 - 77 = 3
80 / 7 = 11, remainder 3
Hope that helped! =)
