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mixer [17]
4 years ago
7

Convert the polar representation of this complex number into its standard form.

Mathematics
2 answers:
yanalaym [24]4 years ago
8 0
2(cos(\frac{7 \pi}{6})+i\ sin(\frac{7 \pi}{6}))\\\\2((-\frac{\sqrt{3}}{2})+i(-\frac{1}{2}))\\\\\\-\sqrt{3}-i
ankoles [38]4 years ago
4 0

Answer:

Option A is correct

The standard form is

2(\cos{\frac{7\pi}{6}}+i\sin{\frac{7\pi}{6}})=-\sqrt3-i

Step-by-step explanation:

Given the polar representation of complex number

2(\cos{\frac{7\pi}{6}}+i\sin{\frac{7\pi}{6}})

we have to convert the above polar representation in standard form.

The standard form of a complex number is a+ib

where a is the real part and bi is the imaginary part.

2(\cos{\frac{7\pi}{6}}+i\sin{\frac{7\pi}{6}})

=2\cos{\frac{7\pi}{6}}+2i\sin{\frac{7\pi}{6}}

=2\times (\frac{-\sqrt3}{2})+2i\times (\frac{-1}{2}}

=-\sqrt3-i

which is required standard form.

Hence, option A is correct.

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