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3 years ago

Evaluate the function at the fiven values of the variables:

Mathematics

1 answer:

Arlecino [84]3 years ago

4 0

Answer:

f(-3)=5x^2+5x*3

-f*3=5x^2+5*3x

-3f=5x^2+15x

f=-5x(x+3)/3

f(-9)=5x^2+5x*3

-f*9=5x^2+5*3x

-9f=5x^2+15x

f=-5x(x+3)/9

Step-by-step explanation:

hope it helps you?

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For positive acute angles A and B, it is known that tan A = 35/12 and sin B = 20/29. Find the value of sin(A - B ) in the simple

almond37 [142]

Answer:

$\displaystyle \sin(A-B)=\frac{495}{1073}$

Step-by-step explanation:

We are given that:

$\displaystyle \tan(A)=\frac{35}{12}\text{ and } \sin(B)=\frac{20}{29}$

Where both A and B are positive acute angles.

And we want to find he value of sin(A-B).

Using the first ratio, we can conclude that the opposite side is 35 and the adjacent side is 12.

Then by the Pythagorean Theorem, the hypotenuse is:

$h = \sqrt{35^2 + 12^2} =37$

Using the second ratio, we can likewise conclude that the opposite side is 20 and the hypotenuse is 29.

Then by the Pythagorean Theorem, the adjacent is:

$a=\sqrt{29^2-20^2}=21$

Therefore, we can conclude that:

So, for A, the adjacent is 12, opposite is 35, and the hypotenuse is 37.

For B, the adjacent is 21, opposite is 20, and the hypotenuse is 29.

We can rewrite sin(A-B) as:

$\sin(A-B)=\sin(A)\cos(B)-\cos(A)\sin(B)$

Using the above conclusions, this yields: (Note that since A and B are positive acute angles, all resulting ratios will be positive.)

$\displaystyle \sin(A-B)=\Big(\frac{35}{37}\Big)\Big(\frac{21}{29}\Big)-\Big(\frac{12}{37}\Big)\Big(\frac{20}{29}\Big)$

Evaluate:

$\displaystyle \sin(A-B)=\frac{735-240}{1073}=\frac{495}{1073}$

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2 years ago

___ L = 240 kL ? A. 24,000 B. 240,000 C. 0.240 D. 2.4

koban [17]

It's b 240000
I'm sorry if wrong I'm not too good at these things

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2 years ago

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boyakko [2]

Answer: andres is 5 years old pls banned him he called e a mean word like the N word

Step-by-step explanation:

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1 year ago

Triangle JKL has vertices J(−2, 2) , K(−3, −4) , and L(1, −2) . Write the coordinate notation for a translation of 8 units right

Dovator [93]

Triangle JKL has vertices J(−2, 2) , K(−3, −4) , and L(1, −2) .

Rule: (x, y)→(x + 8, y + 1 )

J’ (-2, 2) → (-2 + 8, 2 + 1 ) → (6, 3 )
K’ (-3, -4) → (-3 + 8, -4 + 1 ) → (5, -3 )
L’ (1, -2) → (1 + 8, -2 + 1 ) → (9, -1)

J’ (6,3)
K’ (5,-3)
L’ (9,-1)

Hope this helps!

3 0

2 years ago

(4x-1) /2=x+7 4x-1 all over 2 = x +7

Damm [24]

Answer:

x = $\frac{15}{2}$

Step-by-step explanation:

Given

$\frac{4x-1}{2}$ = x + 7 ( multiply both sides by 2 to clear the fraction )

4x - 1 = 2(x + 7) ← distribute

4x - 1 = 2x + 14 ( subtract 2x from both sides )

2x - 1 = 14 ( add 1 to both sides )

2x = 15 ( divide both sides by 2 )

x = $\frac{15}{2}$

7 0

2 years ago