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Anit [1.1K]
3 years ago
14

Solve the system of equations using substitution y=x-1 and y=-2x+5

Mathematics
1 answer:
pav-90 [236]3 years ago
7 0
Since the two equations equal y, set them equal to each other.

x-1=-2x+5

From there, solve for x.

First get x on one side, by using the addition property of equality.

x-1=-2x+5
3x-1=5

Isolate x by adding 1.
3x=6

Lastly get x all by itself by dividing each side by 3.
x=2

You can now substitute your x-value, 2, into one of the equations (or both, if you wish; either one will result in the same answer.)

y=x-1
y=2-1
y=1

OR

y=-2x+5
y=-2(2)+5
y=-4+5
y=1

Final answer:
x=2 and y=1

Any questions or anything you would like me to clarify, feel free to ask :)
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gulaghasi [49]

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(b) The following functions are positive in quadrant III:

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The following functions are negative in quadrant III

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5 0
3 years ago
5 x (h + 3) for h = 2
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Answer:

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Hope this helps :)

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