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3 years ago

If an inscribed angle measures 67°, how would you find the intercepted arc?

1 answer:

3 0

I think you would divide the angle measure by two... Does your question give you options (A,B,C,D)?

EDIT
Multiply by 2

You might be interested in

What was the difference in the starting temperature and the ending temperature

igomit [66]

Answer:

You subtract the final temperature from the starting temperature to find the difference. So if something starts at 50 degrees Celsius and finishes at 75 degrees C, then the change in temperature is 75 degrees C – 50 degrees C = 25 degrees C. For decreases in temperature, the result is negative.

Step-by-step explanation: really not sure how to explain but in my understood thats my answer

7 0

3 years ago

The graph of f(x) is shown below. where is f(x) < 0? write your answer in interval notation.

Bad White [126]

Answer:

The graph of f(x) passes through (1,1) , (2,1.4...), (3,1.7....),(4,2)......

As, this curve is not linear.

To find the graph of a inverse function if a function is given

As we can see that ,

√1=1

√2=1.414..

√3=1.732..

√4=2

it means, √x=y is f(x).

So, to find the inverse of f(x), follow the procedure

Squaring both sides

Replace x by y and y by x to get inverse of f(x)

So,there will be two inverses of f(x)

1. x=√y

2. x= -√y

Domain of g(x)∈[0,∞], means y≥0.

Option A, 2nd graph below. and Option B. 3 rd Graph below is true regarding graph of g(x).

3 0

3 years ago

A sequence has an initial value (I) of -17 and its fourth term (a4) is 35. What is its general equation? Its 14th term?

aleksley [76]

Answer:

The sequence is an Arthemtic Progression

An=A1+(n-1)d

A1 is first term, An is nth term, n is number of term, and d is common difference

therefore

A4=35, A1= -17

A4=A1+(4-1)d

35= -17+3d

35+17=3d

52=3d

52/3=3d/3

14=d

common diffrence(d)=14

The general solution is given by

An= -17+(n-1)14

An= -17+14n-14

An= -31+14n

An= 14n-31

A14 term, means n=14

From An=A1+(n-1)d

A14= -17+(14-1)14

= -17+(13×14)

= -17+182

= 165.

Therfore, the 14th term is 165.

2. A sequence has a CR of 4/5 and its eighth term (a8) is (393216/3125). What is its general equation? Its 3rd term?

solution

common ratio(r)=4/5

eighth term(G8)=393216/3125

From Gn= G1r^(n-1)

G8 means n=8

G8=G1r^(n-1)

393216/3125=G1(4/5)^(8-1)

393216/3125=G1(4/5)^7

G1=(393216/3125)/(4/5)^7

G1=600

The first term is given by G1=600

Therefore

The General equation is given by

The General equation is given by Gn= 600(4/5)^(n-1)

3rd term (G3)

G3= G1(4/5)^(3-1) where n=3,

=600(4/5)^2

=600(16/25)

=384

Therefore, the 3rd term is given by G3= 384.

I have made some Corrections i messed up somewhere.

7 0

3 years ago

What is the horizontal shift for the graph of f(x) = (x - 3)3 + 2? A. Left 2 B. Right 2 C. Left 3 D. Right 3

jarptica [38.1K]

The graph of the function f(x) = (x - 3)^3 + 2 is 3 units to the right of the parent function.
Hence the horizontal shift is right 3.

3 0

3 years ago

How many distinct triangles can be formed for which m∠A = 75°, a = 2, and b = 3?

antiseptic1488 [7]

We can use the Sine Law:a / sin A = b / sin B2 / sin 75° = 3 / sin B2 / 0.966 = 3 / sin B ( after that we will cross multiply )
2 sin B = 3 · 0.9662 sin B = 2.898sin B = 2.898 : 2sin B = 1.499 > 1 ( it is not possible )Answer: A ) No triangles can be formed.

8 0

3 years ago