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bija089 [108]
3 years ago
12

Find the area of the kite

Mathematics
2 answers:
polet [3.4K]3 years ago
7 0

Answer:

\text{The area of kite is }190.44 m^2  

Step-by-step explanation:

Given the kite in which length of diagonals are given

we have to find the area of kite.

Length of diagonals are

p=9.2+9.2=18.4 m

q=6.9+13.8=20.7 m

\text{Area of kite=}\frac{pq}{2}

Area=\frac{18.4\times 20.7}{2}=\frac{380.88}{2}=190.44 m^2

\text{Hence, the area of kite is }190.44 m^2

Elis [28]3 years ago
6 0
d_1=9.2m+9.2m=18.4m\\d_2=6.9m+13.8m=20.7m\\\\Area\ of\ the\ kite:A=\frac{d_1\times d_2}{2}\\\\A=\frac{18.4\times20.7}{2}=9.2\times20.7=190.44\ (m^2)
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Determine wether the function is increasing, decreasing, or constant
evablogger [386]

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Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby. Thi
Dovator [93]

Complete question:

Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby this mention is designed to increase the likelihood that each baby will be a girl, but assume that the method has no effect so the probability of a girl is 0.5. Assume that the group consists of 36 couples.

A) Find the mean and standard deviation for the number of girls in groups of 36 births.

B) Use the range rule of thumb to find the values separating results that are significantly low and significantly high.

C) Is the result of 33 girls significantly high? A result of 33 girls would suggest the method is effective or is not effective?

Answer:

a) mean = 18

Standard deviation =3

b) low range = 12

High range = 24

c) The result of 33 girls is significantly high. Yes, the method is effective.

Step-by-step explanation:

Given:

p = 0.5

n = 36

a) The mean is the product of n and p

Mean u = np

u = 36 * 0.5 = 18

The standard deviation is the square root of the product of n and p&q.

S.d ó = \sqrt{npq}

= \sqrt{np(1-p)}

= \sqrt{36(0.5)(1-0.5)} = \sqrt{9} = 3

b) To find the range rule of thumb:

• For low range

Low range = u - 2ó

= 18 - (2 * 3)

= 12

• High range

= u + 2ó

= 18 + (2*3)

= 24

c) The result is significantly high, because 33 is greater than 24 girls.

A result of 33 girls would prove the method as effective.

8 0
3 years ago
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