Answer:
A. yes, the data represents a function because u have no repeating x values. A function cannot have repeating x values...they can have repeating y values, just not the x ones
Step-by-step explanation:
B. table : (8,8)(12,12)(14,16)(16,16)
look at ur points...when x = 8, y = 8...so the table, when x = 8 has a
value of 8
relation : f(x) = 8x - 5....when x = 8
f(8) = 8(8) - 5
f(8) = 64 - 5
f(8) = 59....and the relation has a value of 59
Therefore, the relation has a greater value when x = 8 <==
C. f(x) = 8x - 5...when f(x) = 19
19 = 8x - 5
19 + 5 = 8x
24 = 8x
24/8 = x
3 = x <==
The general solution of <span>y' + 2xy = (x^3) is y(x) = c1e^(-x^2)
The general solution of </span><span>ydx = (y(e^y) - 2x)dy is x = c1/(y(x))^2 + (e^y(x) ((y(x))^2 - 2y(x) + 2)/(y(x))^2
</span>
The general solution of<span> (dP)/(dt) + 2tP = P + 4t - 2 is P(t) = c1e^(t - t^2) + 2</span>
Answer:
Step-by-step explanation:
<h3>Given information</h3>
<h3>Question 15. f(g(2))</h3>
<u>Substitute values into the first function</u>
<u>Substitute the values of the first function into the second</u>
<h3>Question 16. g(f(2.5))</h3>
<u>Substitute values into the first function</u>
<u />
<u>Substitute the values of the first function into the second</u>
<h3>Question 17. g(f(-5))</h3>
<u>Substitute values into the first function</u>
<u>Substitute the values of the first function into the second</u>
<h3>Question 18. f(g(-5))</h3>
<u>Substitute values into the first function</u>
<u>Substitute the values of the first function into the second</u>
Hope this helps!! :)
Please let me know if you have any questions
Step-by-step explanation:
your friend is closer to the school (b)
it's graph covers less area..
Sorry but I’m just commenting because apparently you have to answer other people’s questions in order to ask questions even when you have Brainley plus ugh
