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3 years ago

The bisector of an obtuse angle forms

Mathematics

2 answers:

mr Goodwill [35]3 years ago

7 0

It forms two acute angles so A

Neporo4naja [7]3 years ago

6 0

Answer: Option 'a' is correct.

Step-by-step explanation:

Since we know that

Obtuse angles are those angles which is lies between 90° and 180°.

And the bisector of an obtuse angle forms acute angles because of the definition of an obtuse angle, their bisectors form acute angle.

As we know that the bisectors divides the angle (here, obtuse angle) into two equal and smaller parts.

So, anyhow, it can be acute angles.

Hence, Option 'a' is correct.

You might be interested in

Which operation is used for the equation down below

mario62 [17]

Answer:

Step-by-step explanation:

2x+8=9

you want to isolate the variable so you subract 8 from both sides

2x=1

now you want x by itself so you divide by 2 on both sides

x=1/2 or x=0.5

Hope this helped :)

3 0

4 years ago

How do you solve the system 3x-y z=5, x 3y 3z=-6, and x 4y-2x=12?

dlinn [17]

3x - y + z = 5 . . . (1)
x + 3y + 3z = -6 . . . (2)
x + 4y - 2z = 12 . . . (3)

From (2), x = -6 - 3y - 3z . . . (4)
Substituting for x in (1) and (3) gives
3(-6 - 3y - 3z) - y + z = 5 => -18 - 9y - 9z - y + z = 5 => -10y - 8z = 23 . . (5)
-6 - 3y - 3z + 4y - 2z = 12 => y - 5z = 18 . . . (6)

(6) x 10 => 10y - 50z = 180 . . . (7)
(5) + (7) => -58z = 203
z = 203/-58 = -3.5

From (6), y - 5(-3.5) = 18 => y = 18 - 17.5 = 0.5
From (4), x = -6 - 3(0.5) - 3(-3.5) = -6 - 1.5 + 10.5 = 3

x = 3, y = 0.5, z = -3.5

8 0

4 years ago

Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1

alexandr1967 [171]

Answer:

$a) \simeq 0.3012$ $b) \simeq 0.0494$ c) $\simeq 0.2438$

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, $\frac{1.2}{4}$

= 0.3 collisions per month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

P(X =x) = $\frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}
$

for x ∈ N ∪ {0}

= 0 otherwise --------------------------------------(1)

here, $\lambda = 0.3$ collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

P(X = 0) = $\frac{e^{-0.3}\times {\0.3}^{0}}{0!}
$

$\simeq 0.7408182207$ ------------------------------------(2)

Now, since we are calculating this for 4 months,

so, P(No collision in 4 month period)

= $0.7408182207^{4}$

$\simeq 0.3012$ -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

P(X =1) = $\frac{e^{-0.3}\times {\0.3}^{1}}{1!}
$

$\simeq 0.2222454662$ ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

= $0.2222454662^{2}$

$\simeq 0.0494$ -----------------------------------------(5)

1 collision in 6 months period means

$\frac{1}{6}$ collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6] (which is to be estimated)

= $\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}$

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

$\simeq 0.6543894283$ -------------------------------------------(6)

So,

P(1 collision in 6 month period)

= $0.6543894283^{6}$

$\simeq 0.0785267444$ ------------------------------------------------(7)

So,

P(No collision in 6 months period)

= $(P(X =0)^{6}$

$\simeq 0.1652988882$ ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

$\simeq 0.2438$ ---------------------------------------------(9)

7 0

3 years ago

The length of a rectangular garden ABCD is 9 feet more than its width. It is surrounded by a brick walkway 4 feet wide as shown

Anna71 [15]

Answer:

16.5 ft by 25.5 ft

Step-by-step explanation:

Let w represent the width of the garden in feet. Then w+9 is the garden's length, and w(w+9) represents its area.

The surrounding walkway adds 8 feet to each dimension, so the total area of the garden with the walkway is ...

(w+8)(w+9+8) = w^2 +25w +136

If we subtract the area of the garden itself, then the remaining area is that of the walkway:

(w^2 +25w +136) - (w(w+9)) = 400

16w + 136 = 400 . . .simplify

16w = 264 . . . . . . . . subtract 136

264/16 = w = 16.5 . . . . . width of the garden in feet

w+9 = 25.5 . . . . . . . . . . .length of the garden in feet

5 0

4 years ago

Omar rented a truck for one day. There was a base fee of $18.99, and there was an additional charge of 78 cents for each mile dr

natulia [17]

165.63-$18.99= $146.64

$146.64 / .78€ per mi= 188miles

188 miles is your answer

6 0

3 years ago