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MatroZZZ [7]
3 years ago
7

Elizabeth has 5/6kg of beads. IF she shares the beads between 4 friends, how much kg does each friend receive.

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
4 0

Answer:

5/24 kg

Step-by-step explanation:

5/6 ÷ 4/1 (keep-change-flip)

5/6 x 1/4 = 5/24

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Please can someone help me with this question
sasho [114]

<em>Answer:</em>

<em>r = -</em>\frac{6a}{1-5m^2}<em />

<em>Step-by-step explanation:</em>

<em>Rewrite the equation as </em>\sqrt{x} 6a+r/5r<em>  = m</em>

<em>Remove the radical on the left side of the equation by squaring both sides of the equation.</em>

<em>(</em>\sqrt{\frac{6a+r}{5r} )^{2}<em> = m^2</em>

<em>Then, you simplify each of the equation. </em>

<em>Rewrite: (</em>\sqrt{\frac{6a+r}{5r} )^{2}<em> as </em>\frac{6a+r}{5r} = m^{2}<em />

<em>Remove any parentheses if needed.</em>

<em>Solve for r. </em>

<em>Multiply each term by r and simplify."</em>

<em>Multiply both sides of the equation by  5.</em>

<em>6a+r= m^2r⋅(5)</em>

<em>Remove parentheses.</em>

<em>Move 5   to the left of (m ^2)  r </em>

<em>6a+r=5m^2)r</em>

<em>Subtract  5m^2)r  from both sides of the equation.</em>

<em>6a+r-5m^2)r=0</em>

<em>Subtract  6a  from both sides of the equation.</em>

<em>r-5m^2)r=-6a</em>

<em>Factor  r out of  r-5m^2)r  </em>

<em>r(1-5m^2)=-6a</em>

Divide each term by 1-5m^2 and simplify.

r = - \frac{6a}{1-5m^2}

There you go, hope this helps!

4 0
3 years ago
Regular hexagon ABCDEF is inscribed in circle X and has an apothem that is 6√3 inches long. Use the length of the apothem to cal
TEA [102]
Perimeter is 12*6 =72



7 0
3 years ago
Find an ordered pair (x y) that is a solution to the equation calculator
galina1969 [7]
Pick a value for 'x' then solve for the 'y'

Ex: X=6 then 6-2y=2 then 4=2y then y=2y

So your answer will be 6,2.

Another answer to your question would be 4,1.
7 0
3 years ago
Round to the near at tenth <br> | 3x + 1 | =22
sdas [7]

Answer:

x =7                                    x = -7  2/3

Step-by-step explanation:

| 3x + 1 | =22

Absolute value equations have 2 solutions, one positive and one negative

3x+1 = 22                   3x+1 = -22

Subtract 1 from each side

3x+1-1 =22-1               3x+1-1 = -22-1

3x= 21                         3x = -23

Divide each side by 3

3x/3 = 21/3                      3x/3 = -23/3

x =7                                    x = -7  2/3

6 0
3 years ago
How many minutes did he/she play in all
Lerok [7]
Add the 3 fractions together.
Mixed fractions: 5 3/4 + 2 2/3 + 10 1/6
Convert to improper fractions and then add. Or simply use a calculator.

Total = 223/12 = 18 7/12
5 0
3 years ago
Read 2 more answers
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