What is 1.7¯ expressed as a fraction in simplest form?

The components of vector are ax and ay (both positive), and the angle that it makes with respect to the positive x axis is θ. Fi

Andru [333]

we can use formula

$\theta=tan^{-1}(\frac{a_y}{a_x})$

(a)

we are given

$a_x=12,a_y=12$

now, we can plug values

$\theta=tan^{-1}(\frac{12}{12})$

$\theta=tan^{-1}(1)$

$\theta=\frac{\pi}{4}rad$

(b)

we are given

$a_x=20,a_y=12$

now, we can plug values

$\theta=tan^{-1}(\frac{12}{20})$

$\theta=tan^{-1}(\frac{3}{5})$

$\theta=30.96^{\circ \:}$

(c)

we are given

$a_x=12,a_y=20$

now, we can plug values

$\theta=tan^{-1}(\frac{20}{12})$

$\theta=tan^{-1}(\frac{5}{3})$

$\theta=59.03^{\circ \:}$

6 0

3 years ago

Solve this system of equations by elimination: 8x+9y=48 12x+5y=21

Olin [163]

Answer:

Let's solve your system of equations by elimination.

8x+9y=48;12x+5y=21

Steps:

Multiply the first equation by 5,and multiply the second equation by -9.

5(8x+9y=48)

−9(12x+5y=21)

Becomes:

40x+45y=240

−108x−45y=−189

Add these equations to eliminate y:

−68x=51

Then solve−68x=51for x:

−68x /−68 = 51 /−68 (Divide both sides by -68)

x= −3 /4

Now that we've found x let's plug it back in to solve for y.

Write down an original equation:

8x+9y=48

Substitute

−3 /4

8x+9y=48:

8( −3 /4 )+9y=48

9y−6=48 (Simplify both sides of the equation)

9y−6+6=48+6 (Add 6 to both sides)

9y=54

9y /9 = 54 /9 (Divide both sides by 9) y=6

Answer: x= −3 /4 and y=6

Hope This Helps! Have A Nice Day!!

7 0

3 years ago

As an estimation we are told 5 miles is 8 km. Convert 60 miles to km

noname [10]

Answer:

60 miles to km would be 0.06 kilometer.

Step-by-step explanation:

8 0

3 years ago

Find the equation of a line parallel to y=2x+1 that contains points (14, 3)

Norma-Jean [14]

The equation is y=2x-25

3 0

3 years ago

find the formula for a rational function that satisfies all of the following. its x-intercept is (-3,0). it has a vertical asymp

Norma-Jean [14]

Let that be

$\\ \rm\Rightarrow y=\dfrac{a(f(x))}{g(x)}$

Two vertical asymptotes at -1 and 0

$\\ \rm\Rightarrow y=\dfrac{a(f(x)}{x(x+1)}$

If we simply

$\\ \rm\Rightarrow y=\dfrac{a(f(x)}{x^2+1}$

Denominator has degree 2
Numerator should have degree as 2 and coefficient as 3 inorder to get horizontal asymptote y=3 means the quadratic equation should contain 3x²
But there should be a x intercept at -3 so one zeros should be -3

Find a equation

3x²+9x

Find zeros

3x²+9x=0
3x(x+3)=0
x=0,-3

Horizontal asymptote

3x²/x²
3

So our equation is

$\\ \rm\Rightarrow y=\dfrac{3x^2+9x}{x(x+1)}$

Graph attached

4 0

2 years ago