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Irina18 [472]
3 years ago
9

Witch rate is equivalent to 72/9

Mathematics
1 answer:
satela [25.4K]3 years ago
7 0

Answer:8

Step-by-step explanation:

72/9=8

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A counselor at a community college claims that the mean GPA for students who have transferred to State University is more than 3
Lena [83]

Answer:

t=\frac{3.25-3.1}{\frac{0.3}{\sqrt{36}}}=3  

If we compare the p value and the significance level for example \alpha=1-0.99=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis.

And the best conclusion would be:

a) Yes. The counselor's claim is valid

Because we reject the null hypothesis in favor to the alternative hypothesis.

Step-by-step explanation:

Data given and notation  

\bar X=3.25 represent the sample mean

s=0.3 represent the sample standard deviation

n=36 sample size  

\mu_o =3.1 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is more than 3.1, the system of hypothesis would be:  

Null hypothesis:\mu \leq 3.1  

Alternative hypothesis:\mu > 3.1  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{3.25-3.1}{\frac{0.3}{\sqrt{36}}}=3  

P-value  

The first step is calculate the degrees of freedom, on this case:  

df=n-1=36-1=35  

Since is a one right tailed test the p value would be:  

p_v =P(t_{(35)}>3)=0.00247  

Conclusion  

If we compare the p value and the significance level for example \alpha=1-0.99=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis.

And the best conclusion would be:

a) Yes. The counselor's claim is valid

Because we reject the null hypothesis in favor to the alternative hypothesis.

5 0
3 years ago
Cost 75.09 with a 38% markup
Sophie [7]

Answer:

103.62

Step-by-step explanation:

If I am understanding this question correctly you want the answer for how much the total would be for a 38% markup at a starter price of 75.09.

In which case it would be 103.62.

It is a 28.53 increase.

5 0
3 years ago
Hayden earns $9.50 per hour as a lifeguard.He earns a bonus of $50.00 for taking a training course.How many hours must he work t
mel-nik [20]

Answer: he must work for at least 26.32 hours

Step-by-step explanation:

Let x represent the number of hours that Hayden works as a life guard.

Hayden earns $9.50 per hour as a lifeguard. This means that the amount that he earns for working for x hours would be

9.5x

He earns a bonus of $50.00 for taking a training course. If he takes this bonus cost, the amount that he would earn for working for x hours is

9.5x + 50

Therefore, the number of hours that he must work to earn at least $300.00 would be

9.5x + 50 ≥ 300

9.5x ≥ 300 - 50

9.5x ≥ 250

x ≥ 250/9.5

x ≥ 26.32

4 0
3 years ago
Expand and simplify<br> (3y - 2)(y + 3)
Vedmedyk [2.9K]

Step-by-step explanation:

3y^2 + 7y - 6

5 0
3 years ago
Read 2 more answers
An exceptionally bright high school student has applied for two scholarships: a merit scholarship and an athletic scholarship. H
9966 [12]

Answer:

a) 0.70

b) 0.82

Step-by-step explanation:

a)

Let M be the event that student get merit scholarship and A be the event that student get athletic scholarship.

P(M)=0.3

P(A)=0.6

P(M∩A)=0.08

P(not getting merit scholarships)=P(M')=?

P(not getting merit scholarships)=1-P(M)

P(not getting merit scholarships)=1-0.3

P(not getting merit scholarships)=0.7

The probability that student not get the merit scholarship is 70%.

b)

P(getting at least one of two scholarships)=P(M or A)=P(M∪A)

P(getting at least one of two scholarships)=P(M)+P(A)-P(M∩A)

P(getting at least one of two scholarships)=0.3+0.6-0.08

P(getting at least one of two scholarships)=0.9-0.08

P(getting at least one of two scholarships)=0.82

The probability that student gets at least one of two scholarships is 82%.

4 0
3 years ago
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