Your answer is B. I hope this is helpful!
2.4<7
2.4 / 0.6 = 4
2.4 / 2.4 = 1
4.8<7
4.8 / 0.6 = 8
4.8 / 2.4 = 2
Thus L.H.S = R.H.S that is 2/√3cosx + sinx = sec(Π/6-x) is proved
We have to prove that
2/√3cosx + sinx = sec(Π/6-x)
To prove this we will solve the right-hand side of the equation which is
R.H.S = sec(Π/6-x)
= 1/cos(Π/6-x)
[As secƟ = 1/cosƟ)
= 1/[cos Π/6cosx + sin Π/6sinx]
[As cos (X-Y) = cosXcosY + sinXsinY , which is a trigonometry identity where X = Π/6 and Y = x]
= 1/[√3/2cosx + 1/2sinx]
= 1/(√3cosx + sinx]/2
= 2/√3cosx + sinx
R.H.S = L.H.S
Hence 2/√3cosx + sinx = sec(Π/6-x) is proved
Learn more about trigonometry here : brainly.com/question/7331447
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The total amount paid for the article is Rs2782
<h3>How to determine the amount paid?</h3>
The given parameters are:
Article = Rs 2750
VAT = Rs 32
The amount paid is calculated using:
Amount = Article + VAT
This gives
Amount = 2750 + 32
Evaluate
Amount = 2782
Hence, the total amount paid for the article is Rs2782
Read more about VAT at:
brainly.com/question/20392481
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