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3 years ago

Type an equation that can be used to solve for the missing angles. DO NOT SOLVE.

Mathematics

1 answer:

muminat3 years ago

6 0

Answer:

x°+2x°+(x-24)°=180°

Step-by-step explanation:

The sum of of the interior angles of all triangles add up to 180°

Adding x°, 2x°, and (x-24)° will equal 180

Therefore, an equation that can be used to solve for the missing angles is: x°+2x°+(x-24)°=180°

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Part E 1e. Subtract the binomial 12y2 – 4y3 from the trinomial 7y - 2y3 + 5y2

bazaltina [42]

Answer:

2y^3-7y^2+7y

Step-by-step explanation:

7y - 2y^3 + 5y^2 - ( 12y^2 – 4y^3)

Distribute the minus sign

7y - 2y^3 + 5y^2 - 12y^2 + 4y^3

Combine like terms

2y^3-7y^2+7y

4 0

2 years ago

Which step shows the result of applying the subtraction property of equality?

Scilla [17]

Answer:

First step

Step-by-step explanation:

Subtract the 4 to the other side making the equation

(12x+8)+4=3

12x+8=-1

12x=-9

x=-3/4

7 0

3 years ago

Ayala biked 12.76 miles on Sunday, 3.45 miles on Monday, and 6.52 miles on Tuesday. Over those three days, about how many miles

agasfer [191]

Answer:

23 miles

Step-by-step explanation:

12.76=13

3.45=3

6.52=7

13+3+7=23

3 0

2 years ago

Read 2 more answers

X^2-8x+16 divided by ax-4x numerator

Vedmedyk [2.9K]

Answer:

Given:

1). $x^2-8x+16$ divided by $x-4$

⇒ $\frac{x^2-8x+16}{x-4}$

⇒ $\frac{x^2-2\times x\times 4+4^2}{x-4}$

By factorising numerator by using identity, $(a-b)^2=a^2-2\times a \times b +b^2$

⇒ $\frac{(x-4)^2}{x-4}$

⇒ $\frac{(x-4)\times(x-4)}{x-4}$

⇒ $x-4$ {Answer}

2). $3x^2y$ divided by $6xy^2$

⇒ $\frac{3x^2y}{6xy^2}$

⇒ $\frac{3\times x\times x\times y}{6\times x\times y\times y}$

⇒ $\frac{x}{2y}$ { Answer}

4 0

3 years ago

Write an equation in point slope form for the line with a slope of 3 passes through (1,2)

alexgriva [62]

Answer:

$y-2=3(x-1)$

Step-by-step explanation:

The point-slope form of a line is given as:

$y-y_1=m(x-x_1)$

Where

m is the slope

$x_1$ is the x-coordinate of the point given (passing through the line)

$y_1$ is the y-coordinate of the point given (passing through the line)

Now,

Given,

Slope = m = 3

$x_1$ = 1

$y_1$ = 2

Now, we simply plug these into the formula for point-slope form of a line:

$y-y_1=m(x-x_1)\\y-2=3(x-1)$

This is the point-slope form.

4 0

3 years ago