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r-ruslan [8.4K]
3 years ago
14

The difference between three times a number and seven is twenty. What is the number?

Mathematics
1 answer:
Mama L [17]3 years ago
6 0

Answer:

9

Step-by-step explanation:

(9*3) = 27 which is 20 more than 7

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Mikayla caught a value pack of crackers for $6.72. The value pack had 24 individually wrapped crackers packages. Solve 24x = $6.
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The bar graph shows the numbers and colors of cars in a parking lot. The total number of silver and black cars equal the total n
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3 years ago
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A normal distribution has a mean of 137 and a standard deviation of 7. Find the z-score for a data value of 121. Incorrect Round
Neko [114]

Answer:

The z-score for a data value of 121 is -2.29.

Step-by-step explanation:

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 137, \sigma = 7

Find the z-score for a data value of 121.

This is Z when X = 121. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{121 - 137}{7}

Z = -2.29

The z-score for a data value of 121 is -2.29.

4 0
3 years ago
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A chemical flows into a storage tank at a rate of (180+3t) liters per minute, where t is the time in minutes and 0<=t<=60
Yuliya22 [10]

Answer:

The amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

Step-by-step explanation:

Consider the provided information.

A chemical flows into a storage tank at a rate of (180+3t) liters per minute,

Let c(t) is the amount of chemical in the take at <em>t </em>time.

Now find the rate of change of chemical flow during the first 20 minutes.

\int\limits^{20}_{0} {c'(t)} \, dt =\int\limits^{20}_0 {(180+3t)} \, dt

\int\limits^{20}_{0} {c'(t)} \, dt =\left[180t+\dfrac{3}{2}t^2\right]^{20}_0

\int\limits^{20}_{0} {c'(t)} \, dt =3600+600

\int\limits^{20}_{0} {c'(t)} \, dt =4200

So, the amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

5 0
3 years ago
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