Sub x = 2-y^2 to Q, we get:
Q = 3(2-y^2)*y^2
let y^2 = k
Q = 3(2-k)k = 3(2k-k^2)
2k-k^2 has a max when k = 1
Then y^2 = 1 -> y = 1 or -1
Answer:
there is not enough information to solve
Step-by-step explanation:
You need two ordered pairs to calculate the average rate of change.
Let's say the value of the function at n = 1 is a, and the value of the function at n = 3 is b, then the average rate of change from n = 1 to n = 3 is
(b - a)/(3 - 1) = (b - a)/2
Answer:
$500
Step-by-step explanation:
Today the price of a Jeep is $25,000.
In 1970, the price was $5,000.
We need to find the relative price. It can be calculated as follows :

So, the relative price is $500.
It should be B or C
Step-by-step explanation: