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WITCHER [35]
3 years ago
9

Seven friends picked 7 quarts of blueberries. Three of the friends will share 4 quarts blueberries equally and the other 4 frien

ds will share 3 quarts of the blueberries equally. In which group does each friend get a greater amount of blueberries? Explian your reasoning
Mathematics
1 answer:
densk [106]3 years ago
5 0
In the group of 3 friends, each gets 4/3 quart.
In the group of 4 friends, each gets 3/4 quart.

The friends in the first group get a greater amount of blueberries. Reasoning: 4/3 > 3/4.
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grandymaker [24]

Answer:

4 1/2 cups of flour, 2 1/4 cups of sugar, 1 cup of brown sugar

Step-by-step explanation:

1 1/2 cups flour:3/4 cup of white sugar:1/3brown sugar yields 6 servings. So multiply each amount in the ratio by 3 for 18 servings

6 0
3 years ago
A bus makes a stop at 2:30, letting off 11 people and letting on 4. The bus makes another stop ten
zubka84 [21]

Answer:

14>2

Step-by-step explanation:

6 0
3 years ago
Everyday, Dave eats either a sandwich or pizza for lunch. Over 42 days, Dave had pizza 3 times for every 4 times he had a sandwi
Elenna [48]

Remark

This problem drove 4 of us crazy until one of us made a break through.


Assumptions.

He must eat either 1 pizza a day or 1 sandwich a day. He can't eat 2 of anything during 1 day. So he can't eat 2 pizzas in a day or 2 sandwiches in a day.


Step One

Find the number of days in a cycle.

3 out of 4 days means out of 4 days he chooses Pizza

2 out of 3 days means out of 3 days he chooses a Sandwich.

That means that there are 4 + 3 days in total = 7 days in the cycle.


Step Two

Find the number of Pizzas and the number of Sandwiches he had during the 42 day period.


3/7 * 42 = Pizzas

3*6 = 18 pizzas in 42 days.


4/7* 42 = Sandwiches

4*6 = 24 sandwiches.


In 42 days he ate 24 + 18 = 42 lunches of either pizzas or sandwiches.


Step three This is the key step.

Find the ratio of sandwiches and pizzas for x days.


Every 5 days he either has 3 pizzas or 2 sandwiches. If the total number of days is x then

3/5 * x = Pizzas

2/5 * x = Sandwiches.


Step 4

Equate the results.

Pizzas = sandwiches.

18 + 3/5 x = 24 + 2/5 x Multiply by 5

18*5 + (3/5)*x * 5 = 24 * 5 + (2/5)*x*5

90 + 3x = 120 + 2x Subtract 2x from both sides

90 + 3x - 2x = 120

90 + x = 120 Subtract 90 from both sides.

x = 120 - 90

x = 30 days.


Conclusion

It takes 30 days to even up the number of pizzas with the number of sandwiches.




5 0
3 years ago
There are 4 kinds of plants tulip,fern,cactus,and ficus and 4 kinds of pots clay, metal pot, and wood pot if you randomly pink t
Vesnalui [34]
1 out of 16
you multiply 1/4 and 1/4 because that is the probability for each pot and plant
5 0
3 years ago
P(k)=a^k=2 3 4 find value of a that makes this is a valid probability distribution
Vesna [10]
Sounds like you're asked to find a such that

\displaystyle\sum_{k=2}^4\mathbb P(k)=\mathbb P(2)+\mathbb P(3)+\mathbb P(4)=1

In other words, find a that satisfies

a^2+a^3+a^4=1

We can factorize this as

a^4+a^3+a^2-1=a^3(a+1)+(a-1)(a+1)=(a+1)(a^3+a-1)=0

In order that \mathbb P(k) describes a probability distribution, require that \mathbb P(k)\ge0 for all k, which means we can ignore the possibility of a=-1.

Let a=y+\dfrac xy.

a^3+a-1=\left(y+\dfrac xy\right)^3+\left(y+\dfrac xy\right)-1=0
\left(y^3+3xy+\dfrac{3x^2}y+\dfrac{x^3}{y^3}\right)+\left(y+\dfrac xy\right)-1=0

Multiply both sides by y^3.

y^6+3xy^4+3x^2y^2+x^3+y^4+xy^2-y^3=0

We want to find x\neq0 that removes the quartic and quadratic terms from the equation, i.e.

\begin{cases}3x+1=0\\3x^2+x=0\end{cases}\implies x=-\dfrac13

so the cubic above transforms to

y^6-y^3-\dfrac1{27}=0

Substitute y^3=z and we get

z^2-z-\dfrac1{27}=0\implies z=\dfrac{9+\sqrt{93}}{18}
\implies y=\sqrt[3]{\dfrac{9+\sqrt{93}}{18}}
\implies a=\sqrt[3]{\dfrac{9+\sqrt{93}}{18}}-\dfrac13\sqrt[3]{\dfrac{18}{9+\sqrt{93}}}
6 0
4 years ago
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