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2 years ago

Which statement is true of triangles FGH and JKL?

Mathematics

2 answers:

Mars2501 [29]2 years ago

6 0

Answer:

They are similar because their corresponding angles are congruent and their corresponding sides are proportional in length.

Step-by-step explanation:

From the statements,

∠G≅∠K

∠F≅∠J

∠H≅∠L

The sides of triangle FGH are proportional to those of triangle JKL

FG/JK =GH/KL=FH/JL =1/2

DIA [1.3K]2 years ago

4 0

Answer:

They are similar because their corresponding angles are congruent and their corresponding sides are proportional in length.

Step-by-step explanation:

i took the practice test.

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Which of the following is not a polynomial?

nignag [31]

Answer:

Step-by-step explanation:

A is not a polynomial as the power of x is less than one

3 0

1 year ago

the maximum walking speed S, in feet per second of an animal can be modeled by the equation S=the square root gL where g=32ft/se

swat32

The maximum walking speed of the Giraffe is 1.41 times greater than the maximum walking speed of the Hippopotamus

<h3>Calculating Maximum speed</h3>

From the question, we are to determine how much greater the maximum walking speed of Giraffe is to that of Hippopotamus

From the give information,

The maximum walking speed, S, is given by

S = √gL

Where g = 32ft/sec
and L is the length of the animal's leg

Thus,

For a Giraffe with a leg length of 6 feet

S = √32×6

S = √192

S = 13.856 ft/sec

For a Hippopotamus with a leg length of 3 feet

S = √32×3

S = √96

S = 9.798 ft/sec

Now, we will determine how many times greater 13.856 is than 9.798

13.856/9.798 = 1.41

Hence, the maximum walking speed of the Giraffe is 1.41 times greater than the maximum walking speed of the Hippopotamus

Learn more on Calculating Speed here: brainly.com/question/15784810

#SPJ1

3 0

1 year ago

Find the slope of (0,1) and (2,-3) with this equation<br><br> (Y2-Y1)/(X2-X1)

aalyn [17]

$\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{-3}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-3}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{2}-\underset{x_1}{0}}}\implies \cfrac{-4}{2}\implies -2$